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4 years ago

A Tale f Two Elephants

Physics

1 answer:

Murljashka [212]4 years ago

3 0

Answer:

u need it now?

Explanation:

I'll answer it

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Define the refraction index of a

Andrews [41]

Answer:

see below

Explanation:

refractive index of a medium is defined as the ratio of the speed of light in vacuum to the speed of light in medium

critical angle of glass is 42 means that if the angle of incidence inside the glass is 42 degrees, then the angle of refraction in the optically less dense medium will be 90 degrees

hope this helps

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3 years ago

What happens during

alukav5142 [94]

Answer:

Explanation:

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3 years ago

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A 14.0 g wad of sticky clay is hurled horizontally at a 110 g wooden block initially at rest on a horizontal surface. The clay s

ahrayia [7]

Answer:

86.53 m/s

Explanation:

Given:

Mass of clay (m) = 14.0 g = 0.014 kg

Mass of block (M) = 110 g = 0.110 kg

Initial speed of block (U) = 0 m/s

Sliding distance (d) = 7.50 m

Coefficient of friction between block and surface (μ) = 0.650

Let the initial speed of clay be 'u' and speed of clay and block just after collision be 'v'.

Now, momentum is conserved just before and just after collision.

Momentum just before collision = $mu + 0 = mu$

Momentum just after collision = $(m + M)v$

Therefore, $mu=(M+m)v$ --------- (1)

Now, using newton's second law and we find the acceleration of the system.

The frictional force is given as:

$f=\mu mg=-ma\\\\a=-\mu g$

Now, using equation of motion, we can find the velocity just after collision.

$0^2=v^2+2ad\\\\v=\sqrt{-2ad}\\\\v=\sqrt{-2\times (-\mu g)\times d}\\\\v=\sqrt{2\mu gd}$

Plug in the given values and find 'v'. This gives,

$v=\sqrt{2\times 0.650\times 9.8\times 7.50}\\\\v=\sqrt{95.55}=9.77\ m/s$

Now, using equation (1) and substituting the given values, we get:

$0.014u=(0.014+0.110)\times 9.77\\\\u=\frac{0.124\times 9.77}{0.014}\\\\u=86.53\ m/s$

Therefore, the speed of the clay immediately before impact is 86.53 m/s.

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4 years ago

How much work is done when a girl applies a force of 80 N to move an object 4 m, and then moves the object 1 m back?

eduard

Answer:

$w = \underline{{ \boxed{400 \: J }}}$

Explanation:

$work \: done = \boxed{force \times distance} \\ w = 80 \times (4 + 1) = 80 \times 5 \\ w = \underline{{ \boxed{400 \: J }}}$

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4 years ago

What type of image is formed by a lens if m = -2.0?

MA_775_DIABLO [31]

A real image is smaller than the object

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