Answer:
2. Same force; same impulse; Mini Cooper has greater change in velocity
4. Same momentum
6. It is distributed to the two halves
Explanation:
I will do the even problems as examples.
2. From Newton's third law, we know the bulldozer and Mini Cooper will experience equal but opposite forces. So the magnitude of the force is the same.
Impulse is force times time. Since the force is the same, and the amount of time is the same, then the impulse is the same.
Impulse is equal to change in momentum, or mass times change in velocity. Since the Mini Cooper has the smaller mass, it has the greater change in velocity.
4. Momentum is mass times velocity. The weight of the rover is different on Mars than on Earth, but the mass is still the same. Therefore, if the rover moves at the same speed, it will have the same momentum.
6. The pencil's momentum is conserved. When the pencil breaks in half, half the momentum goes to one half of the pencil, and half the momentum goes to the other half of the pencil.
A is a good example, i suppose.
Answer: a dark (absorption) line
Explanation:
This is as a result of absorption of electromagnetic a specific wavelength. The pattern followed by such lines is characteristic of specific atoms in the path of radiation.
Ur answer is 3 and i'm sure of it
Answer: The two places altitudes are: 16.17 m and 40.67 m
Explanation:
Hi!
Lets call z to the vertical direction (z= is ground) . Then the positions of the balloon and the pellet, using the values of the velocities we are given, are:
![z_b =\text{balloon position}\\z_p=\text{pellet position}\\z_b=(7\frac{m}{s})t\\z_p=30\frac{m}{s}(t-t_0)-\frac{g}{2}(t-t_0)^2\\g=9.8\frac{m}{s^2}](https://tex.z-dn.net/?f=z_b%20%3D%5Ctext%7Bballoon%20position%7D%5C%5Cz_p%3D%5Ctext%7Bpellet%20position%7D%5C%5Cz_b%3D%287%5Cfrac%7Bm%7D%7Bs%7D%29t%5C%5Cz_p%3D30%5Cfrac%7Bm%7D%7Bs%7D%28t-t_0%29-%5Cfrac%7Bg%7D%7B2%7D%28t-t_0%29%5E2%5C%5Cg%3D9.8%5Cfrac%7Bm%7D%7Bs%5E2%7D)
How do we know the value of t₀? This is the time when the pellet is fired. At this time the pellet position is zero: its initial position. To calculate it we know that the pellet is fired when the ballon is in z = 12m. Then:
![t_0=\frac{12}{7}s](https://tex.z-dn.net/?f=t_0%3D%5Cfrac%7B12%7D%7B7%7Ds)
We need to know the when the z values of balloon and pellet is the same:
![z_b=z_p\\(7\frac{m}{s})t =30\frac{m}{s}(t-\frac{12}{7}s)-\frac{g}{2}(t-\frac{12}{7}s)^2](https://tex.z-dn.net/?f=z_b%3Dz_p%5C%5C%287%5Cfrac%7Bm%7D%7Bs%7D%29t%20%3D30%5Cfrac%7Bm%7D%7Bs%7D%28t-%5Cfrac%7B12%7D%7B7%7Ds%29-%5Cfrac%7Bg%7D%7B2%7D%28t-%5Cfrac%7B12%7D%7B7%7Ds%29%5E2)
We need to find the roots of the quadratic equation. They are:
![t_1=2.31s\\t_2=5.81](https://tex.z-dn.net/?f=t_1%3D2.31s%5C%5Ct_2%3D5.81)
To know the altitude where the to objects meet, we replace the time values:
![z_1=16,17m\\z_2=40,67m](https://tex.z-dn.net/?f=z_1%3D16%2C17m%5C%5Cz_2%3D40%2C67m)