Answer:
Q' = 115.2 KJ
Explanation:
Given that
Current I = 10 A
Voltage = 120 V
Time t= 120 s
The energy supplied Q= V I t
Q= 10 x 120 x 120 J
Q= 144 x 1000 J
Q= 144 KJ
The change in the energy ΔEngg = 28.8 kJ
By using energy conservation
Q= Q' + ΔEngg
Q'=Wasted energy
Now by putting the values in the above equation
144 = Q' + 28.8 KJ
Q' = 115.2 KJ
Therefore the waste energy will be 115 kJ.
Answer:
La masa de la mascota es de 11,24 kg.
Explanation:
Dado que la masa total de = 80 kg
Tenemos
Fuerza de fricción = 80 kg × 9.81 × 0.3 = 235.44 N
La mascota salta horizontalmente con una velocidad, v, de 6.0 m / s para dar un movimiento de 1 m a la caja de masa y a la persona
Trabajo realizado por el salto de la mascota = (80 - m) × 9.81 × 0.3
La energía del movimiento del perro = 1/2 × m × v² = Trabajo realizado al saltar de la mascota
1/2 × m × 6² = (80 - m) × 9.81 × 0.3
20943 · m = 235440
m = 235440/20943 = 11,24 kg
Answer:
The scalar product of a and b is: a · b = |a||b| cosθ
Answer:
don't know I just want point for answers
same, stapler, gravity, motion, acceleration
