The magnitude of the charge is 12 N in the opposite direction of the field.
<h3>What is Electric field?</h3>
The term electric field refers to the region in space where the effect of a charge is felt. In this case, we are told that the magnitude of the charge is –0.06 C.
Hence;
E = F/q
F = Eq
F = –0.06 C * 200 N/C
F = 12 N
Hence, the magnitude of the charge is 12 N in the opposite direction of the field.
Learn more about electric field: brainly.com/question/15800304
Answer:
60 m
Explanation:
Case 1:
v₀ = initial speed = 25 mph = 11.2 m/s
v = final speed = 0 m/s
a = acceleration = ?
d = stopping distance = 15 m
using the kinematics equation
v² = v₀² + 2 a d
0² = 11.2² + 2 a (15)
a = - 4.2 m/s²
Case 2 :
v₀ = initial speed = 50 mph = 22.4 m/s
v = final speed = 0 m/s
a = acceleration = - 4.2 m/s²
d = stopping distance = ?
using the kinematics equation
v² = v₀² + 2 a d
0² = 22.4² + 2 (- 4.2) d
d = 60 m
Answer:
a) 30.84m/s
b) 348.32Hz
c) 32.34m/s
d) 289.69Hz
Explanation:
a) If 1 mile=1609,34m, and 1 hour=3600 seconds, then 69mph=69*1609.34m/3600s=30.84m/s
b) Based on Doppler effect:
/*I will take as positive direction the vector */
c)
d)
Answer:
Therefore the magnitude of tangential velocity is 20 m/s.
Explanation:
Tangential velocity:The tangential velocity is the straight line velocity of at any point of rotating object.
It is denoted by
ω= angular velocity
r = radius of rotating object.
Angular velocity: Angular velocity is ratio of angle to time.
Here ω= 50 rad/s and r = 0.4 m
Tangential velocity=(50 ×0.4)m/s
=20 m/s
Therefore the magnitude of tangential velocity is 20 m/s.