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creativ13 [48]
3 years ago
15

Which of the following is a true statement about functions?

Mathematics
1 answer:
raketka [301]3 years ago
3 0

Answer:

B. if F is a fuction then F(2+h)=f(2)+f(h)

Step-by-step explanation:

You might be interested in
The product of 2 and a number increased by 7 is -36
Sholpan [36]
"The product" means you're multiplying the two numbers.
"a number" refers to a variable.
"increased" means you're adding.

2x + 7 = -36
3 0
3 years ago
1.<br> Write a polynomial function in factored form with zeros at -2, 5, and 6.
Hatshy [7]

Answer:

f(x) = (x + 2) (x − 5) (x − 6)

Step-by-step explanation:

f(x) = (x − (-2)) (x − 5) (x − 6)

f(x) = (x + 2) (x − 5) (x − 6)

4 0
2 years ago
Write an equation in the form y=mx for the proportional relationship that passes through the points​ (2, -15) and​ (6, -45).
nydimaria [60]

Answer:

Y=-15/2x

Step-by-step explanation:

7 0
2 years ago
−6x + 14 &lt; −28 OR 9x + 15 ≤ −12. solve for x.
sasho [114]

Answer:

x>7 or x ≤ -3

Step-by-step explanation:

Solving the 1st inequality

-6x +14 < -28 --------------- (Collect like terms)

-6x < -28 - 14

-6x < - 42 -------------------- (Divide both sides by -6)

Note: If you decide an inequality expression by a negative value, the inequality sign changes)

-6x/-6 > -42/-6

x > 7

Solving the 2nd inequality

9x + 15 ≤ −12 ----------- (Collect like terms)

9x ≤ −12 - 15

9x ≤ −27 ------------------(Divide both sides by 9)

9

9x/9 ≤ −27/9

x ≤ -3

Bring both results together, we get

x>7 or x ≤ -3

The final result is complex (i.e. can't be combined together).

4 0
3 years ago
Can someone solve this?
ladessa [460]
  • First question:

Recall that \cos^2x+\sin^2x=1 and \sqrt{x^2}=|x| for all x. So

\sqrt{1-\cos^2x}=\sqrt{\sin^2x}=|\sin x|

\sqrt{1-\sin^2x}=\sqrt{\cos^2x}=|\cos x|

For 0, we expect both \cos x>0 and \sin x>0 (i.e. the sine and cosine of any angle that lies in the first quadrant must be positive). By definition of absolute value, |x|=x if x>0.

So we have

\dfrac{\sqrt{1-\cos^2x}}{\sin x}+\dfrac{\sqrt{1-\sin^2x}}{\cos x}=\dfrac{\sin x}{\sin x}+\dfrac{\cos x}{\cos x}=1+1=\boxed{2}

making H the answer.

  • Second question:

C is always true, because the inequality reduces to x > y.

6 0
3 years ago
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