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NARA [144]
3 years ago
14

In the parallelogram AXYZ, line segment AT = 4y – 2, line segment TY = 6x -12, line segment TX = 14, line segment ZT = 2x + 12.

Find the value of x and y.

Mathematics
1 answer:
Tpy6a [65]3 years ago
8 0
In a parallelogram diagonals bisect each other,
=>AT=TX=>4y-2=14=>4y=14+2=>4y =16=>y=16/4=4
And ZT=TY=>2x+12=6x-12
=>12+12=6x-2x
=>24=4x
=>24/4=X
=>6=X
Hope this helps u...!!!

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Answer:

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<h2>Answer:</h2>

<em><u>Recursive equation for the pattern followed is given by,</u></em>

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<h2>Step-by-step explanation:</h2>

In the question,

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We need to find out the pattern for the recursive equation for the given conditions.

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a_{n}=a_{n-1}+(n-1)^{2}

On checking the equation at the given values of 'n' of, 1, 2, 3 and 4.

<u>At, </u>

<u>n = 1</u>

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which is true.

<u>At, </u>

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<u>At, </u>

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a_{n}=a_{n-1}+(n-1)^{2}\\a_{3}=a_{3-1}+(3-1)^{2}\\a_{3}=a_{2}+4\\a_{3}=5

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<u>At, </u>

<u>n = 4</u>

a_{n}=a_{n-1}+(n-1)^{2}\\a_{4}=a_{4-1}+(4-1)^{2}\\a_{4}=a_{3}+9\\a_{4}=14

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<em><u>Therefore, the recursive equation for the pattern followed is given by,</u></em>

a_{n}=a_{n-1}+(n-1)^{2}

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