To bleep it out! hopefully this helped
Answer:
1. active listening 8. an online journal
2. barrier 1. a strategy for showing other people you are interested in what they are saying and that you understand what they are saying and how they feel about it
3. blog 2. anything that interferes with a message being sent or received
4. communication 5. guidelines for courteous electronic communication
5. netiquette 7. the person who creates or composes a message and delivers it either orally or in writing
6. receiver 9.. a personal belief that one should work hard and do a good job
7. sender 3. an online database of Web pages that can be created or edited by anyone (with permission)
8. wiki 6. the person who receives a message
9. work ethic 4. an exchange of information
Explanation:
The answer is as mentioned above. And these are important words from subject Professional Communication. And like when we talk of an exchange of information, we mean communication. And similarly, other words means as being mentioned above.
You open a new tab for word then close a other document
Bluetooth i believe, not too sure however but its ur best bet
Answer:
#include <iostream>
using namespace std;
void filterEvens(int myArray[]) {
for (int i = 0; i < 8; ++i) {
if(myArray[i]%2==0){
cout<<myArray[i]<<" ";
}
}
}
int main(){
int myArray[8];
for(int i =0;i<8;i++){
cin>>myArray[i];
}
filterEvens(myArray);
return 0;
}
Explanation:
The solution is provided in C++
#include <iostream>
using namespace std;
The function filerEvens is defined here
void filterEvens(int myArray[]) {
This iterates through the elements of the array
for (int i = 0; i < 8; ++i) {
This checks if current element is an even number
if(myArray[i]%2==0){
If yes, this prints the array element
cout<<myArray[i]<<" ";
}
}
}
The main begins here
int main(){
This declares an integer array of 8 elements
int myArray[8];
The following iteration allows input into the array
<em> for(int i =0;i<8;i++){</em>
<em> cin>>myArray[i];</em>
<em> }</em>
This calls the defined function filter Evens
filterEvens(myArray);
return 0;
}
