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Fudgin [204]
3 years ago
7

Manoj's orchard is rectangular of length 39 m and breadth 46 m. If a cost of constructing a wire fence AED 20 per meter, find th

e cost of fencing the Orchard ?
Mathematics
1 answer:
Genrish500 [490]3 years ago
5 0

Answer:

  AED 3400

Step-by-step explanation:

The perimeter of the rectangular orchard is twice the sum of length and width, so is ...

  P = 2(L+W) = 2(39 m +46 m) = 170 m

At a cost of 20/m, the cost of fence is ...

  cost = (AED 20/m)·(170 m) = AED 3400

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4 + 6^2 + 9 ∙ 3 - 10
Korvikt [17]
4+6^2+9•3-10

PEMDAS
P=parentheses
E=exponent
m=multiplication
d=division
a=addition
s=subtraction

*no parentheses in this equation
*exponent = 6^2
6^2=36
4+36+9•3-10
*multiplication = 9•3
9•3=27
4+36+27-10
*addition=4+36+27
4+36+27=67
67-10
*subtraction=67-10
67=10=57

ANSWER=57







please give brainliest itd mean a lot<3
3 0
3 years ago
Mr. Alexander had a negative bank account balance of -$50. He went out to dinner, and spent $23.73. The balance in Mr. Alexander
ollegr [7]

Answer:

-$73.73

Step-by-step explanation:

To get this answer, we must subtract 23.73 from -50, as Mr. Alexander is losing money by spending. Once we subtract, we get -73.73 dollars.

Hope this helps!

6 0
3 years ago
Read 2 more answers
What is 5/20 as a percent if you could give an explanation that would be good but if not thats okay
Liono4ka [1.6K]
5/20 can also be represented as 25/100 or 25%. The can be done by multiplying the top and bottom both by 5 and then dividing our numerator (25) by our denominator(100) to get the %.
3 0
3 years ago
Read 2 more answers
Which numbers are greater than 0.7? 0.37, 0.9, 0.08, 0.69, 0.71
nikitadnepr [17]
Hello!

The following numbers are greater than 0.7:

0.9 and 0.71.
5 0
3 years ago
Josephine has a rectangular garden with an area of 2x2
sergeinik [125]

Answer:

Fourth example, (2x - 3) and (x + 2), are possible dimensions

Step-by-step explanation:

Let's go through all the responses one by one;

First of all the area of the rectangular garden can be computed through length times width, such that:

(x^2 - 3) * (2) = 2x^2 + x - 6,

(2x + 3) * (x-2) = 2x^2 + x - 6,

(2x + 2) * (x-3) = 2x^2 + x - 6,

(2x - 3) * (x + 2) = 2x^2 + x - 6

Now in each of these examples, it should be that the products are equivalent to the area according to the length by width rule, so let's see which is truly the correct dimensions by justifying whether the product is truly equivalent to the area.

First example:

2 * (x^2 - 3) = 2x^2 - 6

Now 2x^2 - 6 ≠ 2x^2 + x - 6 so the first example is not a possibility,

Second example:

(2x + 3) * (x-2) = 2x^2- x - 6

Now 2x^2- x - 6 ≠ 2x^2 + x - 6 so the second example is not a possibility,

Third example:

(2x + 2) * (x-3) = 2x^2 - 4x - 6

Now 2x^2 - 4x - 6 ≠ 2x^2 + x - 6 so the third example is not a possibility,

Fourth example:

(2x - 3) * (x + 2) = 2x^2 + x - 6

Here 2x^2 + x - 6 = 2x^2 + x - 6 so the fourth example can act as possible dimensions

6 0
3 years ago
Read 2 more answers
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