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Fudgin [204]
3 years ago
7

Manoj's orchard is rectangular of length 39 m and breadth 46 m. If a cost of constructing a wire fence AED 20 per meter, find th

e cost of fencing the Orchard ?
Mathematics
1 answer:
Genrish500 [490]3 years ago
5 0

Answer:

  AED 3400

Step-by-step explanation:

The perimeter of the rectangular orchard is twice the sum of length and width, so is ...

  P = 2(L+W) = 2(39 m +46 m) = 170 m

At a cost of 20/m, the cost of fence is ...

  cost = (AED 20/m)·(170 m) = AED 3400

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The number of months until the insect population reaches 40 thousand is 14.29 months and the limiting factor on the insect population as time progresses is 250 thousands.

Given that population P(t) (in thousands) of insects in t months after being transplanted is P(t)=(50(1+0.05t))/(2+0.01t).

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\begin{aligned}\lim_{t \rightarrow \infty}P(t)&=\lim_{t \rightarrow \infty}\frac{50(1+0.05t)}{2+0.01t}\\ &=\lim_{t \rightarrow \infty}\frac{50(\frac{1}{t}+0.05)}{\frac{2}{t}+0.01}\\ &=50\times \frac{0.05}{0.01}\\ &=250\end

(c) Further, we will sketch the graph of the function using the window 0≤t≤700 and 0≤p(t)≤700 as shown in the figure.

Hence, when the population P(t) (in thousands) of insects in t months after being transplanted by P(t)=(50(1+0.05t))/(2+0.01t) then the number of months until the insect population reaches 40 thousand 14.29 months and the limiting factor on the insect population is 250 thousand and the graph is shown in the figure.

Learn more about limiting factor from here brainly.com/question/18415071.

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