2 years ago

Need help

Mathematics

1 answer:

AysviL [449]2 years ago

3 0

-3 -1 i believe is your answer

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Graph f(x)=4x^3-4x-2

maw [93]

Answer:

minimum: ( $\frac{\sqrt{3} }{3} , -\frac{8\sqrt{3} }{9}-2$ )

maximum: (- $\frac{\sqrt{3} }{3} , \frac{8\sqrt{3} }{9}-2$ )

vertical intercept: (0 , -2)

Step-by-step explanation:

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2 years ago

What is (X^3 - 4x^2 + 4x - 1) / (x-1)?

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Answer:

$x^{2} -3x+1$

Step-by-step explanation:

$\frac{x^{3}-4x^{2} +4x-1}{x-1}=\frac{(x-1)(x^{2}-3x+1 )}{x-1}=x^{2}-3x+1$

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3 years ago

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Answer:

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3 years ago

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I think it’s c the bell ringer

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2 years ago

Build the graph of the equation (x+8)(y-10)=0 FIND THE TWO POINTS

alisha [4.7K]

Answer:

Step-by-step explanation:

Theoretically speaking, both equations need to equal 0.

Let's start with (x + 8)

x + 8 = 0

x = 0 - 8

x = -8

Then, let's go to (y - 10)

y - 10 = 0

y = 10 = 0

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So, x = -8 & y = 10

Hope that helps!

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3 years ago