All categories

3 years ago

At which points is the slope negative?

Mathematics

1 answer:

klio [65]3 years ago

5 0

The graph increases untill day 4(slope= positive) and then is stays constant(slope=0). Starting at day 8 the slope changes to be negative

Answer:From the 8th day to the 10th day

Hope this helps:)

You might be interested in

75 is the product of Greg’s height and 5

KatRina [158]

Answer:

Let Greg's height be = x

According to the question;

$= > x \times 5 = 75 \\ \\ = > x = \frac{75}{5} \\ \\ = > x = 15$

So, Greg's height (x) = 15 years

7 0

3 years ago

Read 2 more answers

What is the solution to this system of equations?

kkurt [141]

Answer:

C. x = 5, y = 2

Step-by-step explanation:

Simply plug in each given term in the answer choices, evaluate, then find out which two will make the system of equations authentic, or genuine.

4 0

3 years ago

Jenny and her brother are arguing about who will get the larger peace of cake. They decided to have a coin toss. What is the pos

e-lub [12.9K]

The answer is 1/2 hope i helped

5 0

3 years ago

Read 2 more answers

g Use Stokes' Theorem to evaluate C F · dr where C is oriented counterclockwise as viewed from above. F(x, y, z) = 7yi + xzj + (

Sati [7]

By Stokes' theorem,

$\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S$

where $S$ is any oriented surface with boundary $C$ . We have

$\vec F(x,y,z)=7y\,\vec\imath+xz\,\vec\jmath+(x+y)\,\vec k$

$\implies\nabla\times\vec F(x,y,z)=(1-x)\,\vec\imath-\vec\jmath+(z-7)\,\vec k$

Take $S$ to be the ellipse that lies in the plane $z=y+9$ with boundary on the cylinder $x^2+y^2=1$ . Parameterize $S$ by

$\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath+(u\sin v+9)\,\vec k$

with $0\le u\le1$ and $0\le v\le2\pi$ . Take the normal vector to $S$ to be

$\vec s_u\times\vec s_v=-u\,\vec\jmath+u\,\vec k$

Then we have

$\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S$

$=\displaystyle\int_0^{2\pi}\int_0^1\big((1-u\cos v)\,\vec\imath-\vec\jmath+(u\sin v+2)\,\vec k\big)\cdot\big(-u\,\vec\jmath+u\,\vec k\big)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^{2\pi}\int_0^1(3u+u^2\sin v)\,\mathrm du\,\mathrm dv=\boxed{3\pi}$

5 0

3 years ago

10 * 2020 * 30httkjjj

quester [9]

Answer: 606000 pls mark as brainliest

Step-by-step explanation:

multiply 10x 2020x 30which=606000

4 0

3 years ago