The area of the top surface of the washer is: 160.14 square mm.
<h2>Step-by-step explanation:</h2>The top of the surface is in the shape of a annulus with a outer radius of 10 mm and a inner radius of 7 mm ( since the diameter of the hole is: 14 mm and we know that the radius is half of the diameter)
Now, we know that the area of the annulus region is given by:
where R is the outer radius and r is the inner radius.
Here we have:
Hence, we have:
Answer:
The correct options are 2 and 4.
Step-by-step explanation:
From the given box plot it is clear that
We know that these number divides the data in four equal parts.
25% of the data values lies between 50 and 110. Therefore option 1 is incorrect.
Seventy-five percent of the data values lies between 20 and 50. Therefore option 2 is correct.
It is unlikely that there are any outliers. This statement is not true because the is a huge difference between third quartile and maximum value.
Therefore option 3 is incorrect.
The interquartile range is
Therefore option 4 is correct.
The range is
Range = Maximum-Minimum
Therefore option 5 is incorrect.