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polet [3.4K]
3 years ago
5

Two pairs of jeans cost $75 before tax. If the total tax paid for the two pairs of jeans was $6, what is the percentage of tax?

Mathematics
1 answer:
Anna35 [415]3 years ago
6 0

Answer: 8%

hope this helps! :)

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Joint Frequency because of the fact that it "joins" one number from the column(up and down) and one from the row(side-by-side), hence the two-way table.
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A manufacturing firm tests job applicants. Test scores are normally distributed with a mean of 500 and a standard deviation of 5
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Answer:

The probability that the candidate score is 600 or greater

P(X≥ 600 ) = 0.0228

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

Given mean of the Population = 500

Given standard deviation of the Population = 50

Let 'X' be the random variable in normal distribution

Given  X = 600

Z = \frac{x-mean}{S.D} = \frac{600-500}{50} = \frac{100}{50} =2

<u><em>Step(ii)</em></u>:-

The probability that the candidate score is 600 or greater

P(X≥ 600 ) = P(z≥2)

                  = 0.5 - A(2)

                 = 0.5 -0.4772

                = 0.0228

<u><em>Final answer</em></u>:-

The probability that the candidate score is 600 or greater

P(X≥ 600 ) = 0.0228

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Which of the following is the quotient of the rational expressions shown here? x/x-1 / 1/x 1.
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The quotient of the rational expressions is \rm \dfrac{x^2-x}{x-1}.

<h3>Given that</h3>

Rational Expression; \rm \dfrac{x}{x-1} ÷\rm \dfrac{1}{x+1}

<h3>We have to determine</h3>

Which of the following is the quotient of the rational expressions shown here?

<h3>According to the question</h3>

Rational Expression; \rm \dfrac{x}{x-1} ÷\rm \dfrac{1}{x+1}

Then,

The quotient of the rational expressions is,

\rm \dfrac{x}{x-1} ÷\rm \dfrac{1}{x+1}

\rm =\dfrac{x}{x-1} \times \dfrac{x+1}{1}\\&#10;\\ =\dfrac{x(x-1)}{x\times 1}\\&#10;\\&#10;=\dfrac{x^2-x}{x-1}

Hence, The quotient of the rational expressions is \rm \dfrac{x^2-x}{x-1}.

To know more about Division click the link given below.

brainly.com/question/26163188

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Step-by-step explanation:

According to the question,

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