135 mg*1g/1000mg*10dg/1g=1.35 dg
Answer:
The margin of error for the 90% confidence interval is of 0.038.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error is:

To this end we have obtained a random sample of 400 fruit flies. We find that 280 of the flies in the sample possess the gene.
This means that 
90% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
Give the margin of error for the 90% confidence interval.



The margin of error for the 90% confidence interval is of 0.038.
(a-b)(a+b) because when you reverse the sum you do axa and ax-b xx
Depends on the type of AB, is it AB positive or AB negative
<span>AB-positive: 3.4 percent
<span>AB-negative: 0.6 percent
if you need both add the percentages together</span></span>
I think it should be 90° since x is a right angle