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AURORKA [14]
3 years ago
6

6*12*2+9*12*1+8*1=?twelve

Mathematics
1 answer:
notsponge [240]3 years ago
6 0

Answer: 260

Step-by-step explanation:

Pemdas

So you have to multiply the 6, 12 and 2 than add that number to the product of 9,12 and 1, than add that number to 8 times 1

You get 260

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bagirrra123 [75]
The solution to the problem is as follows:

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I hope my answer has come to your help. Have a nice day ahead and may God bless you always!
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The Mackinac Bridge in Michigan is the third-longest suspension bridge in the United States.
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Which is the best estimate for the length of the car 4 kilometers 4tons 4kilograms 4meters
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What is a necessary step for constructing perpendicular lines through a point off the line?
Nostrana [21]

Answer:

Find another point on the perpendicular line.

Step-by-step explanation:

Given an original line "m", and a point off the line "Q", in order to construct a second line "p", meant to be perpendicular to "m" through the point "Q", fundamentally, the only truly necessary step to construct a perpendicular line through is to find another point on the yet-to-be-found perpendicular line.

Most often, this is accomplished by exploiting the fact that "p" is the set of all points that are equidistant from any pair of points that are symmetric about "p".

Since the symmetry must be about "p", and we don't even know where "p" is, one often finds two points on "m" that are equidistant from "Q".

This can be accomplished by adjusting a compass to a fixed radius (larger than the distance from "Q" to "m"), and making an arc that intersects "m" in two places.  Those two places will be equidistant from "Q", and are simultaneously on line "m".  Thus, these two points, "A" & "B" are symmetric about "p".

Since "A" & "B" are symmetric about "p", they are equidistant from "p", and are on "m".  One could try to find the point of intersection between "p" and "m" through construction, but this is unnecessary.  We need only find a second point (besides "Q") that is equidistant from "A" & "B", which will necessarily be a point on "p", to form the line perpendicular to "m".

To do this, fix the compass with any radius, and from "A" make a large arc generally in the direction of "B", and make the same radius arc from "B" in the direction of "A" such that the two arcs intersect at some point that isn't "Q".  This point of intersection we can call point "T", and the line QT is line "p", the line perpendicular to the original line, necessarily containing "Q".

8 0
2 years ago
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snow_tiger [21]

Answer: -7 = e

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On the right side of the equation the 16's cancel and we have <em>e</em>. On the right side of the equation -112 divided by 16 is -7. Remember that a negative divided by a positive is a negative.

So we have -7 = e which is the solution to our equation.

To check our solution, we can plug -7 in for <em>e</em> in the original equation. So we have -112 = 16 (-7) or -112 = -112 which is a true statement so our answer checks.

5 0
3 years ago
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