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Leya [2.2K]
3 years ago
12

Which of the following equations are written in standard form?

Mathematics
1 answer:
Ostrovityanka [42]3 years ago
8 0
Answers A, C, and D are written in standard form.

Answer B is NOT written correctly in standard form.
You might be interested in
Solve for X<br> 1. -5 = x - (-6)<br> 2. - 30=1.25x<br> 3. -6x=72<br> 4. -4.9=0.7x<br> 5. 3.15=0.45x
Hoochie [10]

Answer: 1. -11=x 2. 24=x 3. x=-12 4. -7 5. x=7


Step-by-step explanation: The answer to first one can be calculated by seeing the - as a -1.

-5 = x - (-6)

-5=x+6

Then subtract 6 from both sides.

-5=x+6

-11=x

The answer to the second can be found simply by dividing both sides by 1.25.

- 30=1.25x

-30/1.25=1.25x/1.25

24=x

The third one can be solved by as we said before dividing both sides by -6.

-6x=72

-6x/-6=72/-6

x=-12

The fourth one can be found again by using division on both sides.

-4.9=0.7x

-4.9/0.7=0.7x/0.7

-7=x

Finally we solve the last one by again doing the same thing dividing both sides by 0.45.

3.15=0.45x

3.15/0.45=0.45x/0.45

7=x

Hope this helps!

3 0
4 years ago
0.1x + 9 ≤ 45 what is x?
soldi70 [24.7K]
Hi Robles928518, 

0,1x + 9 ≤ 45
0,1x ≤ 45 - 9
0,1x ≤ 36
x ≤ 360

x ∈ ] - ∞ ; 360 ]
5 0
3 years ago
Read 2 more answers
A recent study of th graders shows that they prefer social media or sports as a recreational activit
Ainat [17]

Answer:

1500

Step-by-step explanation:

2500/5=500,*3=1500

5 0
3 years ago
The water content of a soil volume is measured four times gravimetrically by oven drying. The mean value of the water content is
expeople1 [14]

Answer:

99% confidence interval for the soil water content is determined by

(0.19474, 0.26926)

Step-by-step explanation:

<u><em>Explanation</em></u>:-

Given mean of the sample = 23.2% = 0.232

Given standard deviation of the sample = 1.0% =0.01

Given sample size 'n' =4

Degrees of freedom = n-1 =4-1 =3

critical value = 0.01

t_{\frac{0.01}{2} } = t_{0.005}  =7.4534

99% confidence interval for the soil water content is determined by

((x^{-} - t_{0.005} \frac{S.D}{\sqrt{n} } , (x^{-} + t_{0.005} \frac{S.D}{\sqrt{n} })

((0.232 - 7.4534\frac{0.01}{\sqrt{4} } , (0.232 + 7.4534 \frac{0.01}{\sqrt{4} })

( 0.232 -0.03726 , 0.232 +0.03726)

(0.19474, 0.26926)

<u><em>Final answer:</em></u>-

99% confidence interval for the soil water content is determined by

(0.19474, 0.26926)

3 0
3 years ago
Whats The answer giving brainliest : )
Gekata [30.6K]

Answer:

A

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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