All categories

4 years ago

Find the tenth term.

Mathematics

1 answer:

ella [17]4 years ago

3 0

Answer:

Step-by-step explanation:

a(10) = the tenth term of the sequence a, is

a(10) = 4 + (-1)^10 = 4 + 1 = 5

You might be interested in

3(y+1) for y=2<br> A. 6<br> B. 9<br> C. 7 <br> D. 8

lubasha [3.4K]

Answer:

Step-by-step explanation:

3(2+1)

3(3)

that how i solved it

8 0

3 years ago

Read 2 more answers

Please help⚠

Anon25 [30]

The answer to the equation is -580

3 0

3 years ago

3+ (-5) explain please i need it asap so... hurry! pls

Anastasy [175]

Answer:

-2

Step-by-step explanation:

3 + -5

Adding -5 is like subtracting 5

3 -5

-2

6 0

3 years ago

Read 2 more answers

SOMEONE HELP ME PLSSSSSSSSSSSSSSSSSSS

fomenos

Answer: drag the first one to the fourth one, drag the second one to the first one,drag the third one to the second one,drag the fourth one to the third one.

Step-by-step explanation:if its wrong then im sorry

3 0

3 years ago

Calculate the side lengths a and b to two decimal places.

Zinaida [17]

Answer:

$a=10.92 units$

$b=14.51 units$

Step-by-step explanation:

We are given that c=6 units

$\angle A=43^{\circ}$

$\angle B=115^{\circ}$

We have to find the side length a and b.

We know that sum of angles of a triangle =180 degrees

$\angle A+\angle B+\angle C=180$

Substitute the values then we get

$43+115+\angle C=180$

$158+\angle C=180$

$\angle C=180-158=22^{\circ}$

sine law: $\frac{a}{sin A}=\frac{b}{sin B}=\frac{c}{sin C}$

$\frac{a}{sin 43^{\circ}}=\frac{6}{sin 22^{\circ}}$

$a=\frac{6}{sin 22^{\circ}}\times sin 43^{\circ}$

$a=10.92 units$

$\frac{b}{sin 115^{\circ}}=\frac{6}{sin 22^{\circ}}$

$b=\frac{6}{sin 22^{\circ}}\times sin 115^{\circ}=14.51$

$b=14.51 units$

6 0

3 years ago