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2 years ago

If 12 key chains cost $35.35, what is the cost of 20 key chains

Mathematics

1 answer:

alina1380 [7]2 years ago

3 0

Answer:

The key chain's are 0.75 each

Step-by-step explanation:

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PLEASE PLEASE PLEASE HELP!!!!! 95 points!!!

zysi [14]

The "rule" being described here is nothing more than the input/output of a mathematical function.

For every input 'x' value supplied, you only need to subtract three to it. For every input 'y' value, you only need to add four to it.

Example: I'll use variable 'm' to represent this function. Variable 'p' will represent the current input point.

m(p) = p[x - 3, y + 4] = p[-7 - 3, 0 + 4] = p[-10, 4]. 'p[]" is just the point.

I tried my best hope that help!

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3 years ago

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H - 9 = 7 <br> explain how you found h

makkiz [27]

Answer:

h=16

Step-by-step explanation:

h-9=7

h=9+7

h=16

I hope this helps.

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3 years ago

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Mykel is picking out some movies to rent, and he has narrowed down his selections to 66 foreign films, 33 children's movies, 66

uranmaximum [27]

Answer:

Mykel can make 2.79 x 10³² different combinations

Step-by-step explanation:

We can solve this problem using combination

The formula for combination is ⁿCₐ = $\frac{n!}{(n - a)!a!}$

where n = total number of choices available

a = number of items being chosen

The total movies Mykel wants is 99.

Taking out the sure 66 drama movies,

Mykel is left with 99 - 66 choices = 33 choices.

The total number of choices he is left with is 66 foreign + 33 children + 44 documentaries = 143 movies

Hence, our n = 143 movies

and a = 33 choices

Hence we do, ¹⁴⁴C₃₃ = $\frac{143!}{(143 - 33)!33!}$ = $\frac{143!}{110!33!}$ 2.79 x 10³² combinations

∴ Mykel can make 2.79 x 10³² different combinations.

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3 years ago

1. What is the correct reason for statement #3?

r-ruslan [8.4K]

Answer:

1) B. Combine-like terms

2) A. Subtraction Property of Equality

3)D. Division Property of Equality

Step-by-step explanation:

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3 years ago

PLEASE HELP ITS MY TRIMESTER TEST MY MOM WILL KILL ME IF I FAIL! <3 WILL MARK BRAINLIST!

Masteriza [31]

Answer:

$area = area \: of \: two \: semi \: circles + area \: of \: rectangle \\ = 2( \frac{1}{2} \pi {r}^{2} ) + (l \times w) \\ = 2( \frac{1}{2} \times 3.14 \times { (\frac{18}{2}) }^{2} ) + (18 \times 4.5) \\ = 254.47 + 81 \\ = 335.5 \: {ft}^{2}$

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3 years ago

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