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Vinvika [58]
3 years ago
12

Help me solve for x and y

Mathematics
2 answers:
Lena [83]3 years ago
8 0
Let's start his with some trigonometry
Cos60=x/30
X=15
Now we can use Pythagorean therom
15^2+b^2=30^2
B(y)= 25.98
riadik2000 [5.3K]3 years ago
6 0
In a 30-60-90 triangle, the shorter side is represented as s, the hypotenuse as 2s, and the longer side as s \sqrt{3}.  Since we are given the hypotenuse's length, we can use it to solve for s:

2s = 30 \\ s = 15

We now have the value of the shorter side, or x in your diagram - 15 units.  Next, we can use s to solve for the long side's length:

s \sqrt{3} = y \\ 
15 \sqrt{3} = y

The length of the longer side, y, is 15 \sqrt{3} (approxiamtely 26) units.

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30 points!!!!!
dlinn [17]
HELLO...!!

Diagonal = ?
Wide = 20 in.
High = 15 in.

Pythagoras formula: D² = H² + W²

D^2=(15)^2+(20)^2\\ \\D^2=225+400\\ \\D^2=625\\ \\D= \sqrt{625}\\ \\D=25\ in.\quad\Longrightarrow\boxed{\boxed{\mathbb{ANSWER\ \checkmark}}}\\ \\ \\\textbf{HOPE\ THIS\ HELPS...!!}
6 0
3 years ago
8m^2+ 40m<br> -------------------<br> 8m
dsp73

Answer:

(m+5)

Step-by-step explanation:

Take out 8m as a factor from the top side of the equation. You are left with \frac{8m(m+5)}{8m}  = m+5

6 0
3 years ago
At the peak of a roller coaster ride, the rider's watch flew off his wrist. The height h in feet of the watch, t seconds after h
defon

Answer:

3 \: s

Step-by-step explanation:

y =  - 16 {x}^{2}  + 32x + 48 \\ 0 =  \frac{ - 16 {x}^{2} + 32x + 48 }{ - 16}  \\0  =  {x}^{2}   - 2x - 3 \\   0= {x}^{2}  - 3x + x - 3 \\  0= x(x - 3)  + 1(x - 3) \\0  = (x + 1)(x - 3) \\  \\ x + 1 = 0  \\ x =  - 1 \\ x - 3 = 0 \\ x = 3

Hope this helps you.

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6 0
3 years ago
Read 2 more answers
Write the slope- intercept form of the equation of the line passing through the point (3,5) and parallel to the line y=3x+6.
seropon [69]

Answer: The gradient of the line passing through is 3, thus the equation of the line becomes y=3x-4.

Step-by-step explanation: The parallel lines gradients that have similar gradients, so now we have the gradient of 3 because its similar to the other gradient. To get the equation of the line we use this equation: y=mx+c, we have to substitute the x and y to get the constant c.

5=3(3)+c

c= -4

y=3x+c

3 0
3 years ago
What is the cross-sectional area of a cement pipe 2 in. thick with an inner diameter of 5 ft? Use pie 3.14.
Paul [167]

Answer:

1.60 ft^{2}

Step-by-step explanation:

Assuming that this is a cylindrical pipe, the area can be determined by applying the formula for calculating the area of a circle.

i.e Area = \pir^{2}

So that,

for the inner part of the pipe,

r = \frac{diameter}{2}

 = \frac{5}{2}

 = 2.5 feet

Area of the inner part of the pipe = \pir^{2}

                                 = 3.14 x (2.5)^{2}

                                 = 19.625

Are of the inner part of the pipe is 19.63 ft^{2}.

Total diameter of the pipe = 5 + 0.2

                                           = 5.2 feet

r = \frac{5.2}{2}

 = 2.6 feet

Area of the pipe = \pir^{2}

                            = 3.14 x (2.6)^{2}

                            = 21.2264

Area of the pipe is 21.23 ft^{2}.

Thus the cross sectional area = Area of the pipe - Area of the inner part of the pipe

                                           = 21.2264 - 19.625

                                           = 1.6014

The cross sectional area of the cement pipe is 1.60 ft^{2}.

6 0
2 years ago
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