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Vinvika [58]
3 years ago
12

Help me solve for x and y

Mathematics
2 answers:
Lena [83]3 years ago
8 0
Let's start his with some trigonometry
Cos60=x/30
X=15
Now we can use Pythagorean therom
15^2+b^2=30^2
B(y)= 25.98
riadik2000 [5.3K]3 years ago
6 0
In a 30-60-90 triangle, the shorter side is represented as s, the hypotenuse as 2s, and the longer side as s \sqrt{3}.  Since we are given the hypotenuse's length, we can use it to solve for s:

2s = 30 \\ s = 15

We now have the value of the shorter side, or x in your diagram - 15 units.  Next, we can use s to solve for the long side's length:

s \sqrt{3} = y \\ 
15 \sqrt{3} = y

The length of the longer side, y, is 15 \sqrt{3} (approxiamtely 26) units.

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Mamont248 [21]

Answer:

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5 0
2 years ago
Write 9 over 24 as a decimal
Andreyy89
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5 0
3 years ago
CAN SOMEONE PLEASE HELP ME ? SO DETERMINE IF THE PRODUCT OF 3 SQAURE ROOT 2 AND 8 SQUARE ROOT 18 IS RATIONAL OR IRRATIONAL. EXPL
Marta_Voda [28]
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Please help asap, will mark Brainliest xoxo
IgorC [24]

Answer/Step-by-step explanation:

Given, b(x) = (\frac{6}{7})^{x}

The table for the function are:

When x = -2

b(-2) = (\frac{6}{7})^{-2}

b(-2) = \frac{1}{(\frac{6}{7})^{2}}

b(-2) = \frac{1}{(\frac{36}{49})}

b(-2) = 1*\frac{49}{36}

b(-2) = \frac{49}{36}

When x = -1

b(-1) = (\frac{6}{7})^{-1}

b(-1) = \frac{1}{(\frac{6}{7})}

b(-1) = 1*\frac{7}{6}

b(-2) = \frac{7}{6}

When x = 0

b(0) = (\frac{6}{7})^{0}

b(0) = \frac{6^0}{7^0}

b(0) = \frac{1}{1}

b(0) = 1

When x = 1

b(1) = (\frac{6}{7})^{1}

b(1) = \frac{6}{7}

When x = 2

b(2) = (\frac{6}{7})^{2}

b(2) = \frac{6^2}{7^2}

b(2) = \frac{36}{49}

3 0
3 years ago
In a direct variation, y = 14 when x = 2. Write a direct variation equation that shows the relationship between x and y.
Luden [163]

Answer:

24.3 y

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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