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3 years ago

PLS HELP!

Mathematics

2 answers:

Sveta_85 [38]3 years ago

7 0

Answer: 5 seconds

Step-by-step explanation I tried pls don’t hate meh

Anastasy [175]3 years ago

6 0

Answer:

si senor I sell orange?

Step-by-step explanation:

or I wash windows?

You might be interested in

If a < 0 and c > b, circle the expression that is greater:

matrenka [14]

Answer:

The expression that is greater is a (b - c)

Step-by-step explanation:

a < 0 and c > b, this means (by the addition property) that c - c > b - c⇒0 > b - c

so for the product a(b - c) we would have a multiplication of a negative number a and another negative number (b - c). We know that the result of the multiplication of two negative numbers is a positive number.

Therefore, a (b - c) > 0

a < 0 and c > b, this means by the addition property that c - b > b - b⇒ c - b > 0

so for a(c - b), we have the negative number a multiplied by the positive number (c - b). We know that the result of the multiplication of a negative number by a positive number is negative.

Therefore a (c - b) < 0

Thus, the expression that is greater is the positive one which is a (b - c)

5 0

3 years ago

Two ratios that are equivalent to 2 : 9

NeTakaya

Answer:

4 : 18, 8 : 36

Step-by-step explanation:

We multiply to find equal ratios.

2 x 2 = 4

9 x 2 = 18

4 x 2 = 8

18 x 2 = 36

We get 4 : 18, 8 : 36.

7 0

3 years ago

Read 2 more answers

An art history professor assigns letter grades on a test according to the following scheme. A: Top 13% of scores B: Scores below

madam [21]

Answer:

The numerical limits for a B grade are 81 and 89, that is, a score between 81 and 89 gets a B grade.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Scores on the test are normally distributed with a mean of 79.7 and a standard deviation of 8.4.

This means that $\mu = 79.7, \sigma = 8.4$

B: Scores below the top 13% and above the bottom 56%

So between the 56th percentile and the 100 - 13 = 87th percentile.

56th percentile:

X when Z has a p-value of 0.56, so X when Z = 0.15. Then

$Z = \frac{X - \mu}{\sigma}$

$0.15 = \frac{X - 79.7}{8.4}$

$X - 79.7 = 0.15*8.4$

$X = 81$

87th percentile:

X when Z has a p-value of 0.87, so X when Z = 1.13.

$Z = \frac{X - \mu}{\sigma}$

$1.13 = \frac{X - 79.7}{8.4}$

$X - 79.7 = 1.13*8.4$

$X = 89$

The numerical limits for a B grade are 81 and 89, that is, a score between 81 and 89 gets a B grade.

4 0

3 years ago

In Friday NIght Funkin' dave and bambi How and What did Dave become 3D?

Ierofanga [76]

Answer:

Step-by-step explanation:

because you rupedid lol

5 0

2 years ago

We considered the differences between the temperature readings in January 1 of 1968 and 2008 at 51 locations in the continental

mr Goodwill [35]

Answer:

$1.1-2.02\frac{4.9}{\sqrt{50}}=-0.30$

$1.1+2.02\frac{4.9}{\sqrt{50}}=2.50$

So on this case the 90% confidence interval would be given by (-0.30;2.50)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=1.1$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s=4.9 represent the sample standard deviation

n=51 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=51-1=50$

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,50)".And we see that $t_{\alpha/2}=2.02$

Now we have everything in order to replace into formula (1):

$1.1-2.02\frac{4.9}{\sqrt{50}}=-0.30$

$1.1+2.02\frac{4.9}{\sqrt{50}}=2.50$

So on this case the 90% confidence interval would be given by (-0.30;2.50)

8 0

3 years ago