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2 years ago

Which of these numbers is a solution of the inequality 3x>18?

Mathematics

2 answers:

Delvig [45]2 years ago

7 0

<h3>hello!</h3>

Let's solve this inequality:-

3x<18

Divide both sides by 3:-

x<6

So numbers less than 6 will make this inequality $\sf{true}$ .

<h3>notes:-</h3>

You haven't listed any numbers, so I don't know what options you have,

Please list the numbers in the comments & I will edit my answer :)

Hope everything is clear; if you need any explanation/clarification, kindly let me know, and I'll comment and/or edit my answer :)

frosja888 [35]2 years ago

4 0

Answer:

The possible answers are all numbers above 6.

Step-by-step explanation:

3x>18

3x/3> 18/3

x> 6

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First term a₁ = 3/2 and common ratio r = 2

Step-by-step explanation:

We need to find the first term and common ratio while we are given third term = 6 and seventh term = 96

Since common ratio is required so, the sequence is geometric sequence

The formula used is: $a_n= a_1r^{n-1}$

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$a_7=a_1r(7-1)\\96=a_1r^6----eq(2)$

Dividing eq(2) and eq(3)

$\frac{96}{6}=\frac{a_1r^6}{a1r2}\\16=\frac{r^6}{r^2}\\16=r^{6-2}\\=> r^4=16\\Taking \ fourth \ root\\ r=2,-2,2i,-2i\\ \ We \ will \ consider \ only \ positive \ value \ of \ r \ i.e \ \textbf{ r= 2}$

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