(a) m<IJK = 90 since segment IK is a diameter
(b) KI = 10 since since LM = KM = KI = 5. The 3 segments are radii.
(c) EP * PL = OP * PF; EP = 2
(d) m<OFH = 178/2 = 89; inscribed angle is half measure of intercepted arc
Answer:
The slope is 2/3 and the y intercept is 5/9
Step-by-step explanation:
This is written in the form
y= mx+b where m is the slope and b is the y intercept
y = 2/3x +5/9
m = 2/3 and b=5/9
The slope is 2/3 and the y intercept is 5/9
It is a function if ALL the x’s are different
Options :
21 mm2
24 mm2
42 mm2
48 mm2
Answer: 24mm^2
Step-by-step explanation:
Given the following :
Side length of larger triangle:
Base = 5mm
Height = 12mm
Side length of smaller triangle :
Base = 4mm
Height = 3mm
Area of triangle :
0.5 × base × height
Area of larger triangle :
0.5 × 12mm × 5mm = 30mm^2
Area of smaller triangle :
0.5 × 4mm × 3mm = 6mm^2
Area of shaded region :
(Area of larger triangle - Area of smaller triangle)
(30mm^2 - 6mm^2) = 24mm^2
We will be using the Angle Addition Postulate in this problem.
This states that if <em>c</em> is on the interior
of <ABD, then m<ABC + m<CBD = m<ABD.
Since m<ABC is 4x + 2, m<CBD is 3x - 7, and m<AVD is 100,
our equation will be 4x + 2 + 3x - 7 = 100.
Solving from here, we first simplify the left side to get 7x - 5 = 100.
Now add 5 to both sides to get 7x = 105.
Dividing both sides by 7, we find that <em>x = 15</em>.
Now we can use the value of x to help us find m<ABC.
Since the m<ABC is 4x + 2, we can substitute a 5 in for x.
This gives us 4(15) + 2 or 60 + 2 which is 62.
So m<ABC is 62°