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MakcuM [25]
3 years ago
8

Miguel's family drinks 3 gallons of milk

Mathematics
1 answer:
Luden [163]3 years ago
7 0
D because ugh I don’t feel like explaining
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Solve for x <br> -3x+8y= 5 <br> 6x - 2y=10<br><br> x= 15/7<br> x=10/7<br> x=5/7<br> x=5/2
oee [108]
I got 10/7 hope helped u
3 0
3 years ago
Help quickkkkkk- I’m terrible at dis stuff
solong [7]

Answer:

Step-by-step explanation:

(x-3)² - 7 = (5-3)²-7

         = 2²-7

          = 4 - 7

          =  -3

3 0
3 years ago
Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level. how m
GalinKa [24]

The addison see to the horizon at 2 root 2mi.

We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.

We have to find the how much farther can addison see to the horizon

<h3>Which equation we get from the given condition?</h3>

d=\sqrt{\frac{3h}{2} }

Where, we have

d- the distance they can see in thousands

h- their eye-level height in feet

For Kaylib

d=\sqrt{\frac{3\times 48}{2} }\\\\d=\sqrt{{3(24)} }\\\\\\d=\sqrt{72}\\\\d=\sqrt{36\times 2}\\\\\\d=6\sqrt{2}....(1)

For Addison h=85(1/3)

d=\sqrt{\frac{3\times 85\frac{1}{3} }{2} }\\d\sqrt{\frac{256}{2} } \\d=\sqrt{128} \\d=8\sqrt{2} .....(2)

Subtracting both distances we get

8\sqrt{2}-6\sqrt{2}  =2\sqrt{2}

Therefore, the addison see to the horizon at 2 root 2mi.

To learn more about the eye level visit:

brainly.com/question/1392973

5 0
3 years ago
Which of the following shows the correct order for -1 2/5, (-1)2, -1.4 and (1/2)2?
Pavlova-9 [17]
What is it supposed to go from

5 0
3 years ago
--<br> Choose the correct simplification of the expression -5x2(4x – 6x2 – 3).
natali 33 [55]

\huge \bf༆ Answer ༄

Let's simply ~

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: - 5 {x}^{2} (4x - 6 {x}^{2}  - 3)

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:( - 5x {}^{2}  \times 4x) - ( - 5 {x}^{2}  \times 6 {x}^{2} ) - ( - 5 {x}^{2}  \times  3)

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: - 20 {x}^{3}    - ( - 30 {x}^{4} ) - ( - 15 {x}^{2} )

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: - 20 {x}^{3}  + 30 {x}^{4}  + 15 {x}^{2}

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:30 {x}^{4}  - 20 {x}^{3}  + 15 {x}^{2}

5 0
2 years ago
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