Answer:
C. Supplementary angles
Step-by-step explanation:
Given
<AFB = 72
Required
Relationship of <AFB and <AFD
<AFB and <AFD are on a straight line and angle on a straight line is 180
From the presentation of both angles,
<AFB + <AFD = 180
Substitute 72 for <AFB
72 + <AFD = 180
Make <AFB the subject of formula
<AFD = 180 - 72
<AFD = 108
Since both <AFB and <AFD sums to 180, then they are supplementary angles.
Hence, the relationship between both angles is supplementary angles
Refer to the diagram shown below.
w = 6 7/8 in = 6.875 in, the width of each device.
d = 3 1/2 in = 3.50 in, the space between teo devices.
The total space needed is
D = 4(w+d) + w
= 5w + 4d
= 5*6875 + 4*3.5
D = 48.375 in or 48 3/8 in
Answer: 48 3/8 inches or 48.375 inches
Respuesta:
25 cm²
Explicación paso a paso:
El área A de un rombo tiene:
A = pq / 2
Donde pyq son las diagonales
Tomando p como la diagonal más grande = 10 cm
Diagonal más pequeña, q = 1/2 * 10 = 5cm
Por lo tanto, el área del rombo es:
A = (10 * 5) / 2
A = 50/2
A = 25 cm²
Ashes2049, are you good at geometry?
Answer:
Rachel
Step-by-step explanation:
We need to measure how far (towards the left) are the students from the mean in<em> “standard deviations units”</em>.
That is to say, if t is the time the student ran the mile and s is the standard deviation of the class, we must find an x such that
mean - x*s = t
For Rachel we have
11 - x*3 = 8, so x = 1.
Rachel is <em>1 standard deviation far (to the left) from the mean</em> of her class
For Kenji we have
9 - x*2 = 8.5, so x = 0.25
Kenji is <em>0.25 standard deviations far (to the left) from the mean</em> of his class
For Nedda we have
7 - x*4 = 8, so x = 0.25
Nedda is also 0.25 standard deviations far (to the left) from the mean of his class.
As Rachel is the farthest from the mean of her class in term of standard deviations, Rachel is the fastest runner with respect to her class.
