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3 years ago

9

Help much needed here

1 answer:

Reil [10]3 years ago

8 0

Hello : let A(-1,5) B(5,-4)<span>
<span>the slope is : (YB - YA)/(XB -XA)
(-4-5)/(5-(-1)) =-9/6 = -3/2</span></span>

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42=-2d+6 I need help.

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Ans given below
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What is the slope of a line perpendicular to the line whose equation is 2x+3y=21. Fully simplify your answer.

erastova [34]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

$2x+3y=21\implies 3y=-2x+21\implies y=\cfrac{-2x+21}{3} \\\\\\ y=\cfrac{-2x}{3}+\cfrac{21}{3}\implies y=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{2}{3}}x+7\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}$

therefore then

$\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{\cfrac{-2}{3}} ~\hfill \stackrel{reciprocal}{\cfrac{3}{-2}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{3}{-2}\implies \cfrac{3}{2}}}$

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2 years ago

If g(x) = -2x5 - 4, find g(2).

miskamm [114]

$g(x)+-2x^5-4$

Substitute the value of x = 2 to the equation:

$g(2)=-2\cdot2^5-4=-2\cdot32-4=-64-4=-68$

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3 years ago