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MissTica
2 years ago
6

Simplify 4+3[5-4 divided by(12-10)]

Mathematics
1 answer:
12345 [234]2 years ago
8 0
12-10=2, 4/2=2, 5-2=3, 3*3=9, 4+9=13
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There are 70 students in the school band. 40% of them are sixth graders, 20% are seventh graders, and the rest are eighth grader
Anon25 [30]

Answer:

The number of students in the school band = 70

40% of students in the school band are sixth graders.

20% of students in the school band are seventh graders.

We have to find the number of band members that are sixth graders.

The number of sixth graders in school band are:

40\% of 70

0.40 \times 70

28

Therefore, there are 28 band members that are sixth graders.


4 0
3 years ago
(3t^2+1)-t^2. How do you do this equation and what’s the answer. Algebra 1.
Oksana_A [137]

2t^2+1

Subtract t^2 from 3t^2 you get 2t^2

which is 2t^2+1 answer

3 0
3 years ago
Given that cot θ = 1/√5, what is the value of (sec²θ - cosec²θ)/(sec²θ + cosec²θ) ?
Bogdan [553]

Step-by-step explanation:

\mathsf{Given :\;\dfrac{{sec}^2\theta - co{sec}^2\theta}{{sec}^2\theta + co{sec}^2\theta}}

\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{{sec}\theta = \dfrac{1}{cos\theta}}}}

\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{co{sec}\theta = \dfrac{1}{sin\theta}}}}

\mathsf{\implies \dfrac{\dfrac{1}{cos^2\theta} - \dfrac{1}{sin^2\theta}}{\dfrac{1}{cos^2\theta} + \dfrac{1}{sin^2\theta}}}

\mathsf{\implies \dfrac{\dfrac{sin^2\theta - cos^2\theta}{sin^2\theta.cos^2\theta}}{\dfrac{sin^2\theta + cos^2\theta}{sin^2\theta.cos^2\theta}}}

\mathsf{\implies \dfrac{sin^2\theta - cos^2\theta}{sin^2\theta + cos^2\theta}}

Taking sin²θ common in both numerator & denominator, We get :

\mathsf{\implies \dfrac{sin^2\theta\left(1 - \dfrac{cos^2\theta}{sin^2\theta}\right)}{sin^2\theta\left(1 + \dfrac{cos^2\theta}{sin^2\theta}\right)}}

\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{cot\theta = \dfrac{cos\theta}{sin\theta}}}}

\mathsf{\implies \dfrac{1 -cot^2\theta}{1 + cot^2\theta}}

\mathsf{Given :\;cot\theta = \dfrac{1}{\sqrt{5}}}

\mathsf{\implies \dfrac{1 - \left(\dfrac{1}{\sqrt{5}}\right)^2}{1 + \left(\dfrac{1}{\sqrt{5}}\right)^2}}

\mathsf{\implies \dfrac{1 - \dfrac{1}{5}}{1 + \dfrac{1}{5}}}

\mathsf{\implies \dfrac{\dfrac{5 - 1}{5}}{\dfrac{5 + 1}{5}}}

\mathsf{\implies \dfrac{5 - 1}{5 + 1}}

\mathsf{\implies \dfrac{4}{6}}

\mathsf{\implies \dfrac{2}{3}}

<u>Hence</u><u>,</u><u> option</u><u> </u><u>(</u><u>a)</u><u> </u><u>2</u><u>/</u><u>3</u><u> </u><u>is </u><u>your</u><u> </u><u>correct</u><u> </u><u>answer</u><u>.</u>

3 0
2 years ago
Find the area of the shaped region
Ganezh [65]

Answer: B

Step-by-step explanation:

A = 0/360 ×π×r^2

=135/360×π×11×11

=142.55 yd^2

5 0
3 years ago
Number 10 help ASAP it’s on probability which I understand but I can’t make out this one question!
iren [92.7K]
The answer will be 25 percent
5 0
3 years ago
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