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3 years ago

5

I need help ASAP!!!!

1 answer:

Ymorist [56]3 years ago

6 0

I started this one then got busy with other things.

z and 71 deg form a same side interior pattern

they're supplementary angles

sum to 180 degrees

z + 71 = 180

z = 180 - 71

z = 109 degrees

z and x are alternate angles

their measures are the same

z = 109 deg so x = 109 deg

y and 71 deg form adjacent angles which are supplementary

sum to 180 degrees

y = 180 - 71 = 109 deg

x = 109 deg, y = 109 deg, z = 109 deg

Part b

w and 88 form a supplementary pair

they add to 180 deg

w = 180 - 88 = 92 deg

v and 101 deg are vertical or opposite angles

They are congruent

So v = 101 deg

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kobusy [5.1K]

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3 years ago

Six cards numbered from 1 to 6 are placed in an empty bowl. First one card is drawn and then put back into the bowl; then a seco

kari74 [83]

Answer:

C. $\frac{1}{18}$

Step-by-step explanation:

Given: Six cards numbered from $1$ to $6$ are placed in an empty bowl. First one card is drawn and then put back into the bowl then a second card is drawn.

To Find: If the cards are drawn at random and if the sum of the numbers on the cards is $8$ , what is the probability that one of the two cards drawn is numbered $5$ .

Solution:

Sample space for sum of cards when two cards are drawn at random is $\{(1,1),(1,2),(1,3)......(6,6)\}$

total number of possible cases $=36$

Sample space when sum of cards is $8$ is $\{(3,5),(5,3),(6,2),(2,6),(4,4)\}$

Total number of possible cases $=5$

Sample space when one of the cards is $5$ is $\{(5,3),(3,5)\}$

Total number of possible cases $=2$

Let A be the event that sum of cards is $8$

$p(\text{A})$ $=\frac{\text{total cases when sum of cards is 8}}{\text{all possible cases}}$

$p(\text{A})=\frac{5}{36}$

Let B be the event when one of the two cards is $5$

probability than one of two cards is $5$ when sum of cards is $8$

$p(\frac{\text{B}}{\text{A}})=\frac{\text{total case when one of the number is 5}}{\text{total case when sum is 8}}$

$p(\frac{\text{B}}{\text{A}})=\frac{2}{5}$

Now,

probability that sum of cards $8$ is and one of cards is $5$

$p(\text{A and B}=p(\text{A})\times p(\frac{\text{B}}{\text{A}})$

$p(\text{A and B})=\frac{5}{36}\times\frac{2}{5}$

$p(\text{A and B})=\frac{1}{18}$

if sum of cards is $8$ then probability that one of the cards is $8$ is $\frac{1}{18}$ , option C is correct.

3 0

3 years ago

What is 9 3/4 as a mixed number and a percent?

krok68 [10]

9 3/4 is a mixed number, and to find a percent it has to be a percent of what. 9 3/4 as a percent alone is 975% if that's what they want.

8 0

3 years ago

Anthony has a combination of 104 nickels and quarters totaling $22. Which system of linear equations can be used to find the num

Butoxors [25]

Answer:

The answer is c and we'll use c to get the actual answers.

A) n + q = 104

B) .05n + .25q = 22 we'll multiply B) by -4

B) -.2n -1q = -88 then we add A)

A) n + q = 104 which equals

.8n = 16

n = 20 nickels

q = 84 quarters

20 nickels = $1

84 quarters = $21

Successful!!!

Step-by-step explanation:

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3 years ago

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iren2701 [21]

Answer:

24?

Step-by-step explanation:

I'm not very good at math and I'm sorry if I'm wrong.

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2 years ago