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dedylja [7]
3 years ago
9

Simplify completely: the quantity 10 times x to the 6th power times y to the third power plus 20 times x to the third power time

s y to the 2nd power all over 5 times x to the third power times y
a.2x^9y64 + 4x^6y^3

b.2x^3y^2 + 4xy

c.2x^3y^2 + 4y^2

d.2x^3y^2 + 4y
Mathematics
1 answer:
eimsori [14]3 years ago
6 0
Correct answer is D.

\frac{10x^6y^3 + 20x^3y^2}{5x^3y}
\\
\\ \text{common in the numerator is }
\\
\\ 10x^3y^2
\\
\\ \text{so}
\\
\\ \frac{10x^3y^2(x^3y + 2)}{5x^3y}
\\
\\ \text{cancel common factors... }
\\
\\ 2y(x^3y + 2) = 2x^3y^2 + 4y
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Consider the inequality -5(x+7) <-10. write an inequalityrepresenting the soulution for x.
Gwar [14]

Answer:

x > -5

Step-by-step explanation:

You multiply both sides by -1

Simplify

Divide both sides by 5

Simplify

Subtract 7 from both sides

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6 0
3 years ago
Alison does 8 math problems in 2 minutes. How long will it take her to do a set of 160 problems?
erastovalidia [21]

Answer:

40 min

Step-by-step explanation:

find unit rateeee  p=problems

8 p= 2 min

8/2=4

so Alison can do 4 math problems per minute

so 160/4= 40 minutes

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5 0
3 years ago
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Convert 89/10 into a mixed number ​
kompoz [17]

Answer:

8 9/10

Step-by-step explanation:

89 goes into 10 8 times.

8x10=80.

89-80=9

So the answer is 8 9/10

6 0
3 years ago
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Please help with this. Thank you very much.
Harman [31]
Here's a graph with 4 points shown.

4 0
3 years ago
Could i have some really really quick help?
nata0808 [166]

Answer:

1125 m

Step-by-step explanation:

Given equation:

h=-5t^2+150t

where:

  • h = height (in metres)
  • t = time (in seconds)

<u>Method 1</u>

Rewrite the equation in vertex form by completing the square:

h=-5t^2+150t

\implies h=-5t^2+150t-1125+1125

\implies h=-5(t^2-30t+225)+1125

\implies h=-5(t-15)^2+1125

The vertex (15, 1125) is the turning point of the parabola (minimum or maximum point).  As the leading coefficient of the given equation is negative, the parabola opens downward, and so vertex is the maximum point.  Therefore, the maximum height is the y-value of the vertex: 1125 metres.

<u>Method 2</u>

Differentiate the function:

\implies \dfrac{dh}{dt}=-10t+150

Set it to zero and solve for t:

\implies -10t+150=0

\implies 10t=150

\implies t=15

Input found value of t into the original function and solve for h:

\implies -5(15)^2+150(15)=1125

Therefore, the maximum height is 1125 metres.

8 0
2 years ago
Read 2 more answers
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