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dedylja [7]
3 years ago
9

Simplify completely: the quantity 10 times x to the 6th power times y to the third power plus 20 times x to the third power time

s y to the 2nd power all over 5 times x to the third power times y
a.2x^9y64 + 4x^6y^3

b.2x^3y^2 + 4xy

c.2x^3y^2 + 4y^2

d.2x^3y^2 + 4y
Mathematics
1 answer:
eimsori [14]3 years ago
6 0
Correct answer is D.

\frac{10x^6y^3 + 20x^3y^2}{5x^3y}
\\
\\ \text{common in the numerator is }
\\
\\ 10x^3y^2
\\
\\ \text{so}
\\
\\ \frac{10x^3y^2(x^3y + 2)}{5x^3y}
\\
\\ \text{cancel common factors... }
\\
\\ 2y(x^3y + 2) = 2x^3y^2 + 4y
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