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3 years ago

6/8 yard and 3/4 are they the same length

Mathematics

2 answers:

kiruha [24]3 years ago

7 0

Yes, 6/8 reduces to 3/4 by dividing the numerator and denominator by 2.

Yuki888 [10]3 years ago

4 0

Yes they are because they are equivalent fractions. In other words, If you simplify 6/8 you get 3/4 because 6/8 ÷ 2/2 = 3/4 or 3/4 x 2/2 = 6/8.
Hope I helped!

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Tell wether the given value is a solution of the inequality.

Lena [83]

N is a placeholder for a number. In this case, it is 4

We will replace every copy of 'n' with '4' and then simplify

So n+8 turns into 4+8 which simplifies to 12

Is 12 less than or equal to 13? Yes it is. Specifically it is less than 13. So n = 4 is part of the solution set.

Here is how you'd write it all out using algebra

$n+8 \le 13$

$4+8 \le 13$

$12 \le 13$

The last inequality is true so the first inequality is true when n = 4. This is another way to see that n = 4 is a solution.

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3 years ago

After you find the solution, how would you check to make sure your answer is correct?

krek1111 [17]

Answer:

Plug in your variables value.

Step-by-step explanation:

For your case, plug in -6 into the y slot

12(5+2y)= -(6-9y) +4y

12(5+2x-6)= -(6-9x-6)+4y see if that works!

5 0

3 years ago

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Is 3ft: 8 sec and 5ft:11 sec equal?

weqwewe [10]

Answer: No they are not equal.

Step-by-step explanation:

6 0

3 years ago

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A sports club has 84 members who learned baseball, and 42 of those members also learned basketball. There are 25 students who di

HACTEHA [7]

<em>The table that shows the relative frequency of data is in the below further explanation.</em>

$\texttt{ }$

<h3>Further explanation</h3>

A set is a clearly defined collection of objects.

To declare a set can be done in various ways such as:

With words or the nature of membership

With set notation

By registering its members

With Venn diagrams

$\texttt{ }$

Multiplying set A x B is by pairing each member of set A with each member of set B.

<u>Example:</u>

Then

A x B = {(1, a), (1, b), (2, a), (2, b), (3, a), (3, b)}

$\texttt{ }$

Union of set A and B ( A ∪ B ) is rewriting each member A and combined with each member B.

Intersection of set A and B ( A ∩ B ) is to find the members that are both in Set A and Set B.

<u>Example:</u>

A ∪ B = {1, 2, 3, 4, 5}

A ∩ B = {3, 4}

Let us now tackle the problem!

$\texttt{ }$

<em>A sports club has 84 members who learned baseball, and 42 of those members also learned basketball.</em>

$\left[\begin{array}{ccc}&Play Baseball&Don't Play Baseball\\Play Basketball&\boxed{42}& \\Don't Play Basketball& & \end{array}\right]$

$\texttt{ }$

Number of members who learned baseball but did not learn basketball will be ( 84 - 42 ) = 42 members

$\left[\begin{array}{ccc}&Play Baseball&Don't Play Baseball\\Play Basketball&42& \\Don't Play Basketball&\boxed{42}& \end{array}\right]$

$\texttt{ }$

<em>There are 25 students who did not learn baseball but learned basketball</em>

$\left[\begin{array}{ccc}&Play Baseball&Don't Play Baseball\\Play Basketball&42&\boxed{25} \\Don't Play Basketball&42& \end{array}\right]$

$\texttt{ }$

<em>8 students did not learn either baseball or basketball</em>

$\left[\begin{array}{ccc}&Play Baseball&Don't Play Baseball\\Play Basketball&42&25 \\Don't Play Basketball&42&\boxed{8} \end{array}\right]$

$\texttt{ }$

<em>Total Number of Students = 42 + 42 + 25 + 8 = 117</em>

$\texttt{ }$

Table of relative frequency

$\left[\begin{array}{ccc}&Play Baseball&Don't Play Baseball\\Play Basketball&\boxed{\frac{42}{117}}&\boxed{\frac{25}{117}} \\Don't Play Basketball&\boxed{\frac{42}{117}}&\boxed{\frac{8}{117}} \end{array}\right]$

$\texttt{ }$

<h3>Learn more</h3>

Mean , Median and Mode : brainly.com/question/2689808
Centers and Variability : brainly.com/question/3792854
Subsets of Set : brainly.com/question/2000547

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Sets

Keywords: Sets , Venn , Diagram , Intersection , Union , Mean , Median , Mode

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3 years ago

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PLZ HELP, DUE TONIGHT!! Find the values of a and b such that f(x) is continuous at x=

Goryan [66]

Answers:

a = 2 and b = -4

============================================================

Explanation:

Let's define the three helper functions

f(x) = ax^2 - b
h(x) = 6
j(x) = 5ax+b

which are drawn from the piecewise function. The g(x) function will change depending on what the input is.

If x < 1, then g(x) = f(x).
If x = 1, then g(x) = h(x)
If x > 1, then g(x) = j(x)

Since we want g(x) to be continuous at x = 1, this must mean the three functions f(x), h(x), j(x) must have the same output value when the input is x = 1.

Because h(x) = 6 is a constant function, the output is always 6 regardless of the input. Therefore, we want f(x) and j(x) to have 6 as their output when x = 1. Or else, the pieces won't connect.

Plug x = 1 into the f(x) function to get

f(x) = ax^2 - b

f(1) = a(1)^2 - b

f(1) = a - b

Set this equal to the desired output of 6 and we end up with the equation a-b = 6. Solving for 'a' leads to a = b+6.

------------

We'll use the same idea for j(x)

j(x) = 5ax + b

j(1) = 5a(1) + b

j(1) = 5a + b

5a+b = 6

5(b+6) + b = 6 ... plug in a = b+6; solve for b

5b+30+b = 6

6b+30 = 6

6b = 6-30

6b = -24

b = -24/6

b = -4

Which then leads to,

a = b+6

a = -4+6

a = 2

------------

Since a = 2 and b = -4, we go from this

$g(x) = \begin{cases}ax^2-b, \ \ x < 1\\6, \ \ x = 1\\5ax+b, \ \ x > 1\end{cases}$

to this

$g(x) = \begin{cases}2x^2+4, \ \ x < 1\\6, \ \ x = 1\\10x-4, \ \ x > 1\end{cases}$

Meaning

f(x) = 2x^2+4 and j(x) = 10x-4

You should find that plugging x = 1 into each of those two functions leads to 6 as the output.

The graph is shown below. Note the red graph f(x) is only drawn when x < 1. Similarly, j(x) is only drawn when x > 1. The orange point represents h(x) which only happens when x = 1. So as the name implies, the piecewise function g(x) is composed of pieces of the three functions f(x), h(x), j(x).

3 0

3 years ago