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1 year ago

14

A prism has three times the volume of a pyramid with the same base and altitude.

1 answer:

sineoko [7]1 year ago

8 0

Answer:

I believe it's true. Good Luck! :)

Step-by-step explanation:

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HELP PLS!!!!!!!!!!!!!!!!!!!

Rama09 [41]

Domain: {-5, 7}
Range: {-9, 4, 8}

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2 years ago

HELP ME ASAP on these math question it’s due after class

lana66690 [7]

I thin the answer is B

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2 years ago

What is one benefit of privately issued student loans?

Leona [35]

Answer:

they have lower interest rates and can be paid back with a lower out of pocket cost

Step-by-step explanation:

Student loans are issued as a kind of financial aid that assist students in their quest to acquire higher education. Private student loans are offered by the private-sector lenders. The alternative to this is a Federal loan.

Actually, private student loans are issued at a lower interest rate. Option of a fixed or variable interest rate may be offered on privately issued student loans. This offers a lower out of pocket cost, hence the answer.

6 0

2 years ago

A city has 5 new houses for every 9 old houses. If there are 35 new houses in the city, how many old houses are there?

Nezavi [6.7K]

Answer:

C.) 63

Step-by-step explanation:

You know what you insisted on me answering, so I'll answer here.

35 ÷ 5 = 7

7 x 9 = 63

7 0

3 years ago

Read 2 more answers

Write a solution in Interval Notation - (you don't have to help me on all, 1 or 2 is fine c: )

Gemiola [76]

QUESTION 1

The given inequality is

$|m|-2>0$

We group like terms to get,

$|m|>2$

This implies that,

$-m>2$ or $m>2$ .

We simplify the inequality to get,

$m$ or $m>2$ .

We can write this interval notation to get,

$(-\infty,-2)\cup (2,+\infty)$ .

QUESTION 2

$|x-4|-3\:>\:5$ .

We group like terms to get,

$|x-4|\:>\:5+3$ .

$|x-4|\:>\:8$

We split the absolute value sign to get,

$-(x-4)\:>\:8$ or $x-4\:>\:8$

This implies that,

$x-4\:$ or $x-4\:>\:8$

$x\:$ or $x\:>\:8+4$

$x\:$ or $x\:>\:12$

We can write this interval notation to get,

$(-\infty,-4)\cup (12,+\infty)$ .

QUESTION 3

The given inequality is

$|6+9x|\leq 24$

We split the absolute value sign to obtain,

$-(6+9x)\leq 24$ or $(6+9x)\leq 24$

This simplifies to

$6+9x\ge -24$ and $6+9x\leq 24$

$9x\ge -24-6$ and $9x\leq 24-6$

$9x\ge -30$ and $9x\leq 18$

$x\ge -\frac{10}{3}$ and $x\leq 2$

$-\frac{10}{3}\leq x\leq2$

We write this in interval form to get,

$[-\frac{10}{3},2]$

QUESTION 4

The given inequality is

$|1-5a|>29$

We split the absolute value sign to get,

$-(1-5a)>29$ or $1-5a>29$

This simplifies to,

$1-5a\:$ or $1-5a\:>\:29$

This implies that,

$-5a\:$ or $-5a\:>\:29-1$

$-5a\:$ or $-5a\:>\:28$

$a\:>\:6$ or $a\:$

We write this in interval notation to get,

$(-\infty,-\frac{28}{5})\cup (6,+\infty)$

7 0

3 years ago