Answer:
Frost (Lessee) and Ananz (Lessor)
The circumstance that would require Frost to classify and account for the arrangement as a finance lease is:
c. The economic life of the computers is three years.
Explanation:
a) Data:
Annual lease payments = $8,000
Present value of the minimum lease payments = $13,000
Fair value of the computer = $14,000
The economic life of the computers = 3 years
The lease period = 2 years
b) One of the conditions for classifying the lease arrangement as a finance lease is that the lease term of 2 years forms a significant part of the asset's useful life of 3 years. Other conditions include:
Firstly, ownership of the asset is transferred to the lessee at the end of the lease term. The second condition is that the lessee can purchase the asset below its fair value.
Answer: The FOUR (4) "fundamental factors" that marketers us to identify "market segmementation" are:
___________________________________________________
1) demographic segmentation ;
2) geographic segmentation ;
3) psychographic segmentation ; AND:
4) behavioral segmentation .
___________________________________________________
Answer:
One company pays 100%, the other re-reimburses 50%
Explanation:
If an environmental assessment found that the two companies share joint and several liability for a hazardous materials cleanup.
What could happen if the two of them don't agree to cooperate in the cleanup is that one of the companies will eventually settle the costs fully while the other party will have to reimburse the party that pays, 50%.
The paying company could make claims because the environmental impact assessment has already found both companies jointly liable. hence each company ought to jointly share the costs
Answer:
this is a cost minimization problem, but it is missing some numbers, so I looked for similar questions (see attached PDF):
minimization equation = 20x₁ + 22x₂ + 18x₃ (costs per ton)
where:
x₁ = mine I
x₂ = mine II
x₃ = mine III
the constraints are:
4x₁ + 6x₂ + x₃ ≥ 54 (high grade ore)
4x₁ + 4x₂ + 6x₃ ≥ 65 (low grade ore)
x₁, x₂, x₃ ≤ 7 (only 7 days per week)
using solver, the optimal solution is
2x₁, 7x₂, and 5x₃
a. The number of days Mine I should operate = <u>2 days
</u>
b. The number of days Mine Il should operate = <u>7 days
</u>
c. The number of days Mine III should operate = <u>5 days
</u>
d. The total cost of the operation for next week = <u>$284,000</u>