<span>The definition of a perfect cube is a number that is the result of multiplying an integer by itself three times
Hope it helps</span>
To solve this problem, we need to use the Pythagorean Theorem, which states that a^2 + b^2 must equal c^2. "a" is the length of one of the legs (shorter sides of the triangle) and "b" is the length of the other leg. "c" is the length of the hypotenuse.
a = y = 36.25cm
b = x = 20.93cm
a^2 + b^2 = c^2
(36.25)^2 + (20.93)^2 = c^2
1314.0625 + 438.0649 = c^2
√1752.1274 = √c^2
c = 41.8584209 ≈ 41.86
So your final answer is...
The length of the hypotenuse is about 41.86 cm.
Answer:
Price > 100$
Price > 150$
Step-by-step explanation:
Let us assume that x% off of price y$ is better than x$ off.
Hence, 
Hence, y > 100
Therefore, when the price is more than 100$, then only x% off on the price is better than x$. (Answer)
Again, assume that 20% off on price y$ is better than 30$ off.
Hence, 
⇒ y > 150$
Therefore, when the price is more than 150$, then only 20% of on the price is better than 30$ off. (Answer)
Answer:
9*(6+7)
Step-by-step explanation:
First, we have to find the Greatest Common Factor (GCF), to do this we have to see all the factors of 54 and 63 and find the greatest factor that they have in common.
Factors of 54
1,2,3,6,9,18,27,54
Factors of 63
1,3,7,9,21,63
The GCF is 9 because is the greatest factor that is common to both numbers.
Now we have to divide 54/9 and 63/9
54/9 = 6
63/9 = 7
So now we can write the product of the GCF and another sum:
9*(6+7)
<em>We can prove this by solving both expressions:</em>
<em>54+63 = 9*(6+7)</em>
<em>117 = 9*13</em>
<em>117 = 117 </em>
<em>The results are equal so we prove it is right.</em>
<em>The</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>√</em><em>7</em><em>4</em><em> </em><em>units</em><em>.</em>
<em>Pl</em><em>ease</em><em> </em><em>see</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em> </em><em>for</em><em> full</em><em> solution</em>
<em>H</em><em>ope</em><em> it</em><em> helps</em>
<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>
