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Sav [38]
3 years ago
6

Sally is given the information ƒ(1)= 0, ƒ(-2)=0 and ƒ(3)=0. which are the factors of the polynomial?

Mathematics
1 answer:
MatroZZZ [7]3 years ago
8 0
F(1) = 0 tells you that wherever you see an x, you put in a one. When you do, the answer comes out as 0

So one of he factors for f(x) is
f(x) = (x -1) * g(x) 
If you put an 1 into (x - 1) you get (1 - 1) = 0
The whole thing goes to zero when that happens.

If you split up g(x) so that when x = - 2, the whole polynomial goes to 0 just as what happened with x = 1

f(x) = (x - 1) (x + 2) * h(x)

When x = 3 the same thing happens.
f(x) = (x - 1)(x + 2)(x - 3) and that's your complete answer.
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Please show how to compute these values. Thank you.
alekssr [168]

Answer: ln ( 40) *100

Step-by-step explanation:

Substituting 140 in the equation,

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How to convert 1 1/2
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Step-by-step explanation:

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3 0
3 years ago
Angle m AOC=108° m AOB=3x+4° m BOC=8x-28°<br><br> Find m AOB
Alex787 [66]

Hello from MrBillDoesMath!

Answer:

40



Discussion:

A diagram is always appreciated!

Assuming that

mAOC = mAOB    + mBOC       =>

108      = (3x + 4)  +  (8x - 28)    =>  combine common terms

108      = (3x + 8x) + (4 - 28 )     =>

108      = 11x - 24                        =>   add 24 to both sides

132     = 11x                                 =>

x = 132/11 = 12


So mAOB = 3x + 4 = 3(12) + 4 = 36 + 4 = 40



Thank you,

MrB

4 0
3 years ago
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