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Lina20 [59]
3 years ago
9

What are two different ways you could find the value of a? Explain these methods.

Mathematics
2 answers:
Maurinko [17]3 years ago
7 0

Answer:

Sample Response: You could use the Pythagorean theorem, since you know the length of the hypotenuse is 9 + 16 = 25 units and the length of one leg is 15 units. To find the value of a, use the relationship that the the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the legs. You could also use the geometric mean (leg) theorem, which states that the length of the hypotenuse is to the length of an adjacent leg as that adjacent leg length is to the length of its corresponding segment in the hypotenuse. So you could write and solve the proportion 25/a = a/6.

Step-by-step explanation:

Ulleksa [173]3 years ago
4 0
See the attached figure to better understand the problem

we know that

1) First way to find the value of a
in the triangle ABC
<span>applying the Pythagorean theorem
AC</span>²=AB²+BC²--------> BC²=AC²-AB²-----> BC²=25²-15²-----> BC²=625-225
BC²=400--------> BC=20 units
a=BC
a=20 units

2) Second way to find the value of a

in the triangle ABD

AB²=AD²+BD²--------> BD²=AB²-AD²-----> BD²=15²-9²---> BD²=144
BD=12 units

in the triangle BDC
a=BC
BC²=BD²+DC²-----> 12²+16²----> 144+256------> BC²=400
BC=20 units
a=20 units

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4x-y=10 and y=2x-2 answers
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4x - y = 10, y = 2x - 2

4x - (2x -2) = 10

4x - 2x + 2 = 10

2x = 8

x = 4

4(4) - y = 10

-y = -6

y = 6

So x = 4 y= 6

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3 years ago
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Oxana [17]

Answer:

The equation shows the relationship between a planet’s orbital period, T, and the planet’s mean distance from the sun, A, in astronomical units, AU. If planet Y is twice the mean distance from the sun as planet X, by what factor is the orbital period increased?

Step-by-step explanation:

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Answer:

Step-by-step explanation:

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3 years ago
Y=? What is Y? Please help me!
kumpel [21]
Answer:   y = 6 mi.  .
______________________________________________
Explanation:
______________________________________________
Area of a triangle = (½) * (base) * (height) ;

or,  A = (½) * b * h ;  or,  A = b*h / 2 ;
_____________________________________
Given:  A = 24.3 mi ² ;
           b = 8.1 mi 
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Find the height, "h" ;  (in units of "miles", or , "mi" ).
__________________________
   Plug in the known values into the formula:

24.3 mi ² = (½) * (8.1 mi) *(h) ;
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Solve for "h" (height) ;
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(½) * (8.1 mi) = 4.05 mi  ;
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Rewrite: 
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24.3 mi² = (4.05 mi) *(h) ;  Solve for "h" ;
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 Divide each side of the equation by "(4.05 mi)" ; to isolate "h" on one side of the equation ; and to solve for "h" ; 
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   24.3 mi²  / 4.05 mi  = (4.05 mi) *(h)  / 4.05 mi ;
                                 
              →  6 mi  = h ;  ↔  h = 6 mi. 

              →      h = y = 6 mi. 
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7 0
3 years ago
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balandron [24]

Answer:

-1/4

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-8-(-5))/(0-(-12))

m=(-8+5)/(0+12)

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