Hello!!
So, the point slope equation is y-y₁=m(x-x₁)
In order to solve this with the points (-3,2) and (2,1), you need to find the slope.
The equation to find the slope is m=(y₂-y₁)/(x₂-x₁):
m=(2-1)/(-3-2)
m= -1/5
So your slope is-1/5
Now, using the point slope equation I stated earlier, ^^^ plug in either of the points you were given (Either -3,2 or 2,1) and your slope or m value (-1/5)
I'll show you both of the possible equations:
1) Using (-3,2)
y-(2)=m(x-(-3)) OR y-(2)=m(x+3)
Add 2 to both sides
y=mx+5
Answer is y=mx+5
2) Using (2,1)
y-(1)=m(x-(2))
Add 1 to both sides
y=mx-1
Answer is y=mx-1
Hope this helps!!!!
The coordinates called Y=INTERCEPT or the INITIAL VALUE.
hope i help you
:)
Maybe... A= L * W , L * W = A, and W * L = A
Well there product has to be negative.