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Volgvan
3 years ago
9

URGENT HELP MEEEEE!!!:D

Mathematics
2 answers:
sp2606 [1]3 years ago
4 0

Answer: C: 3rd degree polynomial wit 3 terms.

Step-by-step explanation: The polynomial has 3 terms and the highest degree is 3.

professor190 [17]3 years ago
4 0

C. Third degree polynomial with three terms.

Terms are, by definition, the number of nonzero coefficients for powers of x. In this case, there are 3 nonzero coefficients (3 terms) because -1=-1x^0. For example, 2x^3 has one term, but 0 has 0 terms.

The degree of a polynomial is the highest power involved in the expression. In this case, it's 4x^3, so the degree is 3.

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I need help it is due today
faltersainse [42]
The reason why the trails must be in quadrant 2 or 3 is because the coordinates start with a negative number. Quadrant 2= (-,+) and quadrant 3= (-,-)
8 0
3 years ago
In a sample of 57 temperature readings taken from the freezer of a restaurant, the mean is 29.6 degrees and the population stand
Natalka [10]

Answer:

(29.14 ; 30.06)

Step-by-step explanation:

Given that'

Sample size (n) = 57

Mean (m) = 29.6

Population standard deviation (σ) = 2.7

Confidence interval = 80%

= (1 - 0.8) / 2 = 0.1

Mean ± z * σ/√n

Using the Z probability calculator : Z0. 1 = 1.28

Hence,

29.6 ± 1.28 * (2.7 / √57)

29.6 - (1.28 * 0.3576237) ; 29.6 + (1.28 * 0.3576237)

29.142241664 ; 30.057758336

(29.14 ; 30.06)

8 0
3 years ago
HELP!:
algol [13]

Answer:

she can  spend 3.00 dollar on he last chocolate

Step-by-step explanation:

14.00-3.00=11.00

11.00-5.00=6.00

6.00-2.00=4.00

4.00-1.00=3.00

8 0
3 years ago
It would help a lot, and if able, please explain
Ksju [112]
Let one side of the square be x
all sides of the square are equal
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3 years ago
Read 2 more answers
In Exercises 10 and 11, points B and D are points of tangency. Find the value(s) of x.<br>​
Lemur [1.5K]

In both cases,

AB^2=AD^2

(as a consequence of the interesecting secant-tangent theorem)

So we have

10.

(4x+7)^2=(6x-3)^2

16x^2+56x+49=36x^2-36x+9

20x^2-92x-40=0

5x^2-23x-10=0

(5x+2)(x-5)=0\implies\boxed{x=5}

(omit the negative solution because that would make at least one of AB or AD have negative length)

11.

(4x^2-18x-10)^2=(x^2+x+4)^2

16x^4-144x^3+244x^2+360x+100=x^4+2x^3+9x^2+8x+16

15x^4-146x^3+235x^2+352x+84=0

(x-7)(3x+2)(5x^2-17x-6)=0\implies\boxed{x=-\dfrac23\text{ or }x=7}

(again, omit the solutions that would give a negative length for either AB or AD)

7 0
3 years ago
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