Select all the expressions that are equivalent to 10x + 4 - (6x - 1)

Mathematics

1 answer:

Travka [436]3 years ago

3 0

Answer:

4x + 5

Step-by-step explanation:

10x + 4 - 6x + 1

= 4x + 5

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Explain (in words) what you would do to find the missing value in the equation. You do not find the missing number! Equation: ?

maks197457 [2]

Answer:

The missing value = $23\frac{1}{24}$

Step-by-step explanation:

Given - Equation: ? + 59 5/8= 82 2/3

To find - Explain (in words) what you would do to find the missing value in

the equation. You do not find the missing number.

Proof -

Let the missing number = x

So, the equation becomes x + $59\frac{5}{8}$ = $82\frac{2}{3}$

⇒x = $82\frac{2}{3}$ - $59\frac{5}{8}$

= $\frac{248}{3} - \frac{477}{8}$

= $\frac{1984 - 1431}{24}$

= $\frac{553}{24}$

= $23\frac{1}{24}$

⇒x = $23\frac{1}{24}$

∴ we get

The missing value = $23\frac{1}{24}$

Explanation -

Here we have given the ? with addition of number that is equation to some number.

We just have to subtract the two numbers to find the missing value , as we do above.

5 0

3 years ago

Find an equation for the plane that is tangent to the surface z equals ln (x plus y )at the point Upper P (1 comma 0 comma 0 ).

alexira [117]

Let $f(x,y,z)=z-\ln(x+y)$ . The gradient of $f$ at the point (1, 0, 0) is the normal vector to the surface, which is also orthogonal to the tangent plane at this point.

So the tangent plane has equation

$\nabla f(1,0,0)\cdot(x-1,y,z)=0$

Compute the gradient:

$\nabla f(x,y,z)=\left(\dfrac{\partial f}{\partial x},\dfrac{\partial f}{\partial y},\dfrac{\partial f}{\partial z}\right)=\left(-\dfrac1{x+y},-\dfrac1{x+y},1\right)$