1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
FromTheMoon [43]
3 years ago
9

X + y = 0 , x - y = -16 . what's x and what's y? (coordinates)

Mathematics
1 answer:
Darina [25.2K]3 years ago
4 0
X + y = 0
x = - y

x- y = -16
y = x + 16
You might be interested in
A pharmaceutical company receives large shipments of aspirin tablets. The acceptance sampling plan is to randomly select and tes
DerKrebs [107]

Answer:

a) The probability that this whole shipment will be​ accepted is 30%.

b) Many of the shipments with this rate of defective aspirin tablets will be rejected.

Step-by-step explanation:

We have a shipment of 3000 aspirin tablets, with a 5% rate of defects.

We select a sample of size 48 and test for defectives.

If more than one aspirin is defective, the batch is rejected.

The amount of defective aspirin tablets X can be modeled as a binomial distribution random variable, with p=0.55 and n=48

We have to calculate the probabilities that X is equal or less than 1: P(X≤1).

P(X\leq1)=P(X=0)+P(X=1)\\\\\\P(0)=\binom{48}{0}(0.05)^0(0.95)^{48}=1*1*0.0853=0.0853\\\\\\P(1)=\binom{48}{1}(0.05)^1(0.95)^{47}=48*0.05*0.0897=0.2154\\\\\\P(X\eq1)=0.0853+0.2154=0.3007

8 0
3 years ago
If QS bisects PQT, SQT=(8x- 25),PQT=(9x+34), and SQR=112, find each measure.
Goryan [66]

The values of the angles are; x = 12°, m∠PQS = 71°, m∠PQT = 142° and m∠TQR = 41°

<h3>What are the measure of the each angle?</h3>

The required angles; x, m∠PQS, m∠PQT, and m∠TQR

The given parameters are bisects ∠PQT

m∠SQT = (8·x - 25)°

m∠PQT = (9·x + 34)°

m∠SQR = 112°

We have;

m∠PQT = m∠SQT + m∠PQS (Angle addition postulate)

m∠SQT ≅ m∠PQS (Angles formed by angle bisector are congruent)

m∠SQT = m∠PQS  by Definition of congruency

m∠PQT = 2 × m∠SQT

Therefore;

(9·x + 34)° = 2 × (8·x - 25)° = (16·x - 50)°

Collecting like terms gives:

(34 + 50)° = 16·x - 9·x = 7·x

7·x = 84°

x = 84°/7 = 12°

x = 12°

m∠SQT = (8·x - 25)°

Therefore;

m∠SQT = (8 × 12 - 25)° = 71°

m∠SQT = 71°

m∠PQT = 2 × m∠SQT

∴ m∠PQT = 2 × 71° = 142°

m∠PQT = 142°

m∠PQS = m∠SQT (Angles formed by the same bisector )

∴ m∠PQS = m∠SQT = 71°

m∠PQS = 71°

m∠SQR = m∠SQT + m∠TQR (Angle addition postulate)

m∠SQT = 71°

∴  m∠SQR = 112° = 71° + m∠TQR

m∠TQR = 112° - 71° = 41°

m∠TQR = 41°

Learn more about angles here:

brainly.com/question/2882938

#SPJ1

4 0
2 years ago
What is the constant proportionality of 3 cans and 9 balls
Masja [62]
The constant proportionality is whats left over
3 0
4 years ago
Solve 3x+4+7x+8+7x3+7x3
kodGreya [7K]
The answer is ERROR i tried it by hand and by calculator and both answers ended up as ERROR 
3 0
3 years ago
Read 2 more answers
The points (8,-10) and (6,w) fall on a line with the slope of -2. What is the value of w?
ella [17]
W = -6
You get the formula from (8, -10) and the slope.
7 0
4 years ago
Other questions:
  • Three friends were working on a project. Cindy completed 4/8 of the project. Kim completed 3/8 of the project. Sandy completed 1
    15·1 answer
  • How will you write 9*9*9*9*9 as an exponential equation?
    5·2 answers
  • Write the formula for a triangle with a height of 2 1/2 and a 13 in base
    7·1 answer
  • Correct me if im wrong or i have something missed something? Please and thank you!
    14·1 answer
  • What is the area of the shape below? Hint: use the formula: A =1/2 h (b1 + b2) *
    9·1 answer
  • The perimeter of a rectangle can be found using the equation P = 2L + 2W, where P is the perimeter, L is the length, and W is th
    10·2 answers
  • Someone please help and choose correct answer
    14·1 answer
  • Please help!
    6·1 answer
  • Which is equivalent to <br> 4(x + 5)<br><br><br> 4x + 9<br> 4x + 20<br> 4x + 5
    15·2 answers
  • If f(x) = 1/9x-2, what is f^-1(x)?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!