There are two numbers whose sum is 64. The larger number subtracted from 4 times the smaller number gives 31. Then the numbers are 45 and 19
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Given that, There are two numbers whose sum is 64.
Let the number be a and b in which a is bigger.
Then, a + b = 64 ------ eqn (1)
The larger number subtracted from 4 times the smaller number gives 31.
4 x b – a = 31
4b – a = 31 ----- eqn (2)
We have to find the numbers.
So, from eqn (2)
a = 4b – 31
Subatitute a in (1)
4b – 31 + b = 64
On solving we get
5b = 64 + 31
5b = 95
b = 19
So, b = 19, then eqn 1
a + 19 = 64
On simplification,
a = 64 – 19
a = 45
Hence, the two numbers are 45 and 19
Alright...simple...showing all steps.. ;)
You have the equations...
2x+y=7
and
3x+5y=14
To be able to even solve for any of the variables...multiply the equations by...2...and..3...
2x+y=7----*3--> 6x+3y=21
and
3x+5y=14-----*2--->6x+10y=28
Thus,
6x+3y=21
-
6x+10y=28
=========
-7y=-7
y=1
Now, plug y back into any of the original equations....we'll use 2x+y=7 in this case....
2x+(1)=7
2x+1=7
-1 -1
2x=6
x=3
Thus, the point of intersection for these two equations is (3,1)
Answer:
(2,2) and (0,-2)
Step-by-step explanation:
Use the website desmos for questions like graphing
Answer:
2(x+9)
Step-by-step explanation:
2x+18
find the common number which can fit into 2x and 18
in this case the number is 2
so; 2(x+9)
Reduce the expression, if possible, by canceling the common factors.
Exact Form: 22/15
Decimal Form: 1.46
Mixed Number Form: 1/715
