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2 years ago

PLEASE HELP, WILL MARK BRAINLIEST

Mathematics

1 answer:

Advocard [28]2 years ago

5 0

Answer:

A, B, D

Step-by-step explanation:

25% of 37

= 25/100 × 37

= 1/4 × 37

= 0.25 × 37

= 9.25

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36+36+36+36+36 ps i know this but this is way easyer

nika2105 [10]

<em>Answer,</em>

<em>-Laura :-)</em>

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3 years ago

Which equation has a zero slope and y-intercept of -2?

slava [35]

Answer:

It is D

Step-by-step explanation:

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2 years ago

Find the radius, and the approximate circumference and area of the circle below. (Use 3 for \pi)

Marina CMI [18]

Answer:

Circ=37.704, Area= 112.112

Step-by-step explanation:

Circumference= pi *Diameter

Taking pi=3.142, Diameter=12

Circ=3.142*12=37.704

Area= pi * r^2

Area= 3.142*6*6=112.112

4 0

2 years ago

Please help solve this system of equations

stepan [7]

Make a substitution:

$\begin{cases}u=2x+y\\v=2x-y\end{cases}$

Then the system becomes

$\begin{cases}\dfrac{2\sqrt[3]{u}}{u-v}+\dfrac{2\sqrt[3]{u}}{u+v}=\dfrac{81}{182}\\\\\dfrac{2\sqrt[3]{v}}{u-v}-\dfrac{2\sqrt[3]{v}}{u+v}=\dfrac1{182}\end{cases}$

Simplifying the equations gives

$\begin{cases}\dfrac{4\sqrt[3]{u^4}}{u^2-v^2}=\dfrac{81}{182}\\\\\dfrac{4\sqrt[3]{v^4}}{u^2-v^2}=\dfrac1{182}\end{cases}$

which is to say,

$\dfrac{4\sqrt[3]{u^4}}{u^2-v^2}=\dfrac{81\times4\sqrt[3]{v^4}}{u^2-v^2}$

$\implies\sqrt[3]{\left(\dfrac uv\right)^4}=81$

$\implies\dfrac uv=\pm27$

$\implies u=\pm27v$

Substituting this into the new system gives

$\dfrac{4\sqrt[3]{v^4}}{(\pm27v)^2-v^2}=\dfrac1{182}\implies\dfrac1{v^2}=1\implies v=\pm1$

$\implies u=\pm27$

Then

$\begin{cases}x=\dfrac{u+v}4\\\\y=\dfrac{u-v}2}\end{cases}\implies x=\pm7,y=\pm13$

(meaning two solutions are (7, 13) and (-7, -13))

8 0

2 years ago

Question 9 (1 point)

Luden [163]

Answer:

Step-by-step explanation:

16x-80+18=4x+22

16x-62=4x+22

12x-62=22

12x=84

x=7

8 0

3 years ago