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german
2 years ago
9

Is one angle is 30° then what is the measure of its complement

Mathematics
2 answers:
Vaselesa [24]2 years ago
8 0

Complementary angles are adjacent angles which add to equal 90 degrees. Adjacent angles are angles which share a vertex and a side.

Since the sum of complementary angles is always 90°, you can subtract 30 from 90 to find the missing angle measure.

90 - 30 = 60

<h3>Answer:</h3>

The measure of its complement is 60°.

zaharov [31]2 years ago
3 0

Answer:

90-30=60

Step-by-step explanation:

The measure is 60°.

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2 3/8 x 3 3/4 divided by 2 2/3
Butoxors [25]

Answer:

57/32

Step-by-step explanation:

171/32 divided by 2 2/3

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3 years ago
This table shows the linear relationship of the cost in dollars, y, of buying snack packets, x.
Karolina [17]

Answer:$1.25

Step-by-step explanation:

2 divided by 1.60=$1.25

3 divided by 2.40= $1.25

5 divided by 4.00= $1.25

8 divided by 6.40 = $1.25

3 0
2 years ago
\large -6x+6y=6<br> \large 6x+3y=12
Kaylis [27]

Answer:

the solution of the system is:

x = 1 and y = 2.

Step-by-step explanation:

I suppose that we want to solve the equation:

-6*x + 6*y = 6

6*x + 3*y = 12

To solve this, we first need to isolate one of the variables in one of the equations.

Let's isolate y in the first equation:

6*y = 6 + 6*x

y = (6 + 6*x)/6

y = 6/6 + (6*x)/6

y = 1 + x

Now we can replace this in the other equation:

6*x + 3*(1 + x) = 12

6*x + 3 + 3*x = 12

9*x + 3 = 12

9*x = 12 - 3 = 9

x = 9/9 = 1

Now that we know that x = 1, we can replace this in the equation "y = 1 + x" to find the value of y.

y = 1 + (1)  = 2

Then the solution of the system is:

x = 1 and y = 2.

6 0
3 years ago
Prove that :( 1 + 1/<img src="https://tex.z-dn.net/?f=tan%5E%7B2%7DA" id="TexFormula1" title="tan^{2}A" alt="tan^{2}A" align="ab
Aliun [14]

Answer:

See explanation

Step-by-step explanation:

Simplify left and right parts separately.

<u>Left part:</u>

\left(1+\dfrac{1}{\tan^2A}\right)\left(1+\dfrac{1}{\cot ^2A}\right)\\ \\=\left(1+\dfrac{1}{\frac{\sin^2A}{\cos^2A}}\right)\left(1+\dfrac{1}{\frac{\cos^2A}{\sin^2A}}\right)\\ \\=\left(1+\dfrac{\cos^2A}{\sin^2A}\right)\left(1+\dfrac{\sin^2A}{\cos^2A}\right)\\ \\=\dfrac{\sin^2A+\cos^2A}{\sin^2A}\cdot \dfrac{\cos^2A+\sin^A}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A}\cdot \dfrac{1}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A\cos^2A}

<u>Right part:</u>

\dfrac{1}{\sin^2A-\sin^4A}\\ \\=\dfrac{1}{\sin^2A(1-\sin^2A)}\\ \\=\dfrac{1}{\sin^2A\cos^2A}

Since simplified left and right parts are the same, then the equality is true.

3 0
3 years ago
PLEASE HELP ME OUT <br> EASY POINTS HERE :)
liubo4ka [24]

Answer: A

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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