$22222222 { { { { { { { { { { { { { { { { { { { { { { { { { { { { { { { { { { { { { { { { {?}^{2} }^{2} }^{2} }^{2} }^{2} }^{2} }^{2} }^{2} }^{2} }^{2} }^{2} }^{2} }^{2} }^{2} }^{2} }^{2} }^{2} }^{2} }^{2} }^{2} }^{2} }^{2} }^{2} }^{2} }^{2} }^{2} }^{2} }^{2} }^{2} }^{?} }^{?} }^{?} }^{?} }^{?} }^{?} }^{?} }^{?} }^{?} }^{?} }^{?} }^{?}$

3 0

3 years ago

Nemo and Dory are meeting Crush at the tide pool. Nemo must swim 6 ¾ miles while Dory must swim 4 1/2 miles to reach their desti

gayaneshka [121]

Answer:

1.5 times.

Step-by-step explanation:

6.75 / 4.5 = 1.5.

5 0

3 years ago

Which of the following symbols will make a true sentence when inserted in the blank? 4/15___0.26

Sauron [17]

Answer:D

Step-by-stepA explanation: if you simply the fraction by 4/15. The answer is 0.26

The solution is equal to both numbers.

3 0

3 years ago

A car insurance company has determined that 8% of all drivers were involved in a car accident last year. Among the 15 drivers li

svetlana [45]

Answer:

There is an 11.3% probability of getting 3 or more who were involved in a car accident last year.

Step-by-step explanation:

For each driver surveyed, there are only two possible outcomes. Either they were involved in a car accident last year, or they were not. This means that we solve this problem using binomial probability concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

In this problem

15 drivers are randomly selected, so $n = 15$ .

A success consists in finding a driver that was involved in an accident. A car insurance company has determined that 8% of all drivers were involved in a car accident last year. This means that $\pi = 0.08$ .

What is the probability of getting 3 or more who were involved in a car accident last year?

This is $P(X \geq 3)$ .

Either less than 3 were involved in a car accident, or 3 or more were. Each one has it's probabilities. The sum of these probabilities is decimal 1. So:

$P(X < 3) + P(X \geq 3) = 1$