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Igoryamba
3 years ago
15

2/6 + 1/8 A) 11/24 B) 3/14 C) 5/24 D) 8/18

Mathematics
1 answer:
raketka [301]3 years ago
4 0
So with these two fractions you're gonna have to find the LCD (lowest common denominator) before you start adding them. With 6 and 8, the LCD is 24.

So with the numerator and denominator of \frac{2}{6} multiply them by 4. It'll look like this \frac{2}{6} * \frac{4}{4} = \frac{8}{24}

As for \frac{1}{8}, do the same except multiply by 3. It'll look like this: \frac{1}{8} * \frac{3}{3} = \frac{3}{24}.

Now add the new fractions together: \frac{8}{24} + \frac{3}{24} = \frac{11}{24}

A is the answer
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10.368

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Use the zero product property to find the solutions to the equation x^2-13x+30=0
Softa [21]

Answer:

D)  x = 3 , x= 10.

Step-by-step explanation:

Given  : x²-13x+30=0

To find : Use the zero product property to find the solutions to the equation.

Solution : We have given

x²-13x+30=0

On factoring

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On taking x common from first two terms and -3 from last two terms .

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On grouping

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x -3 = 0

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3 0
3 years ago
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Find the inverse of the given function.
kodGreya [7K]

For this case we must find the inverse of the following function:

f (x) = - \frac {1} {2} \sqrt {x + 3}

We follow the steps below:

Replace f(x) with y:

y = -\frac {1} {2} \sqrt {x + 3}

We exchange the variables:

x = - \frac {1} {2} \sqrt {y + 3}

We solve for "y":

- \frac {1} {2} \sqrt {y + 3} = x

Multiply by -2 on both sides of the equation:

\sqrt {y + 3} = - 2x

We raise both sides of the equation to the square to eliminate the radical:

(\sqrt {y + 3}) ^ 2 = (- 2x) ^ 2\\y + 3 = 4x ^ 2

We subtract 3 from both sides of the equation:

y = 4x ^ 2-3

We change y by f ^ {- 1} (x):

f ^ {- 1} (x) = 4x ^ 2-3

Answer:f ^ {- 1} (x) = 4x ^ 2-3

7 0
4 years ago
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