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Igoryamba
3 years ago
15

2/6 + 1/8 A) 11/24 B) 3/14 C) 5/24 D) 8/18

Mathematics
1 answer:
raketka [301]3 years ago
4 0
So with these two fractions you're gonna have to find the LCD (lowest common denominator) before you start adding them. With 6 and 8, the LCD is 24.

So with the numerator and denominator of \frac{2}{6} multiply them by 4. It'll look like this \frac{2}{6} * \frac{4}{4} = \frac{8}{24}

As for \frac{1}{8}, do the same except multiply by 3. It'll look like this: \frac{1}{8} * \frac{3}{3} = \frac{3}{24}.

Now add the new fractions together: \frac{8}{24} + \frac{3}{24} = \frac{11}{24}

A is the answer
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When the area in square units of an expanding circle is increasing twice as fast as its radius in linear units, the radius is...
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Answer:

c. \frac{1}{\pi}

Step-by-step explanation:

We have been given that the area in square units of an expanding circle is increasing twice as fast as its radius in linear units

We will use derivatives to solve our given problem.

We know that area (A) of a circle is equal to A=\pi r^2.

Let us find derivative of area function with respect to time.

\frac{dA}{dt}=\frac{d}{dt}(\pi r^2)

Bring out constant:

\frac{dA}{dt}=\pi \frac{d}{dt}(r^2)

Using power rule and chain rule, we will get:

\frac{dA}{dt}=\pi(2r)* \frac{dr}{dt}

\frac{dA}{dt}=2\pi r*\frac{dr}{dt} Here \frac{dr}{dt} represents change is radius with respect to time.

We have been given that area of an expanding circle is increasing twice as fast as its radius in linear units. We can represent this information in an equation as:

\frac{dA}{dt}=2\frac{dr}{dt}

2\pi r* \frac{dr}{dt}=2\frac{dr}{dt}

2\pi r=2

\frac{2\pi r}{2\pi}=\frac{2}{2\pi}

r=\frac{1}{\pi}

Therefore, the radius is \frac{1}{\pi} and option 'c' is the correct choice.

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3 years ago
Which of the following expressions has a simplified value of 3a – 2?
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3 0
3 years ago
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Answer:

x = 22/15

Step-by-step explanation:

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Combine like terms

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Divide by 6

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