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3 years ago

13

D) (4 radical din 2 - radical din 2 ) × radical 2 + radical 2 × radical 18

1 answer:

olga_2 [115]3 years ago

3 0

D. (4√(2) - √(2)) × √(2) + (2) × √(18)
3√(2) × √(2) + 2√(2) × 3√(2)
3(2) + 6(2)
6 + 12
18

E. √(3) × (2√(5) + 3√(5)) - √(5) × (√(3) + 2√(3))
√(3) × 5√(5) - √(5) × 2(3)
√(3) × 5√(5) - √(5) × 6
5√(15) - 6√(5)

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Dima020 [189]

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Step-by-step explanation:

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If possible step by step explanation. thank you!

elixir [45]

Answer:

A

Step-by-step explanation:

$\frac{(3x^{2} )^\frac{1}{2} }{3^\frac{1}{2} } =3$

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Remember that $\frac{x^b}{x^c} =$ x^(b-c)

Using that $\frac{3^\frac{1}{2}x }{3^\frac{1}{2} }$ =3^(1/2x-1/2)=3^((x-1)/2)

$3^\frac{x-1}{2} =3^1$

So we can say: $\frac{x-1}{2} =1$ , because the bases are the same

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