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Elden [556K]
2 years ago
6

1.

Mathematics
2 answers:
oksian1 [2.3K]2 years ago
6 0

Answer:

Answer is 2

{ \rm{4x + 2 > 10}} \\  \\ { \rm{4x < 8}} \\  \\ { \rm{x < 2}}

kogti [31]2 years ago
6 0
The answer is 2 I know this because i know this
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If T(n)=6n-1what is the first term
OleMash [197]
So if you find the 1st term, you should write 1 instead of n
T1 = 6.1 -1
T1= 6-1
T1= 5
Hope it helps!
#MissionExam001
3 0
3 years ago
What is the trigonometric derivative of Y=2sinx-tanx
Alchen [17]
\bf y=2sin(x)-tan(x)\implies \cfrac{dy}{dx}=2cos(x)-sec^2(x)
7 0
3 years ago
Solve for x. Show each step of the solution. <br><br> 4(8-x)-32=98-5(3x+24)
Firlakuza [10]

Answer: x=−2

Step-by-step explanation:

Let's solve your equation step-by-step.

4(8−x)−32=98−5(3x+24)

Step 1: Simplify both sides of the equation.

4(8−x)−32=98−5(3x+24)

(4)(8)+(4)(−x)+−32=98+(−5)(3x)+(−5)(24)(Distribute)

32+−4x+−32=98+−15x+−120

(−4x)+(32+−32)=(−15x)+(98+−120)(Combine Like Terms)

−4x=−15x+−22

−4x=−15x−22

Step 2: Add 15x to both sides.

−4x+15x=−15x−22+15x

11x=−22

Step 3: Divide both sides by 11.

11x /11 = −22 /11

x=−2

8 0
3 years ago
Find the measures of the complementary angles that satisfy each case. One of the angles is 3 times larger than the other.
Nookie1986 [14]

Answer:

22.5° and 67.5°

Step-by-step explanation:

The sum of complementary angles equal 90°.

Given that one of the complementary angles is 3 times larger than the other, let "x" represent the other angle.

Thus, the following expression can be written to represent this case:

x + 3x = 90

Solve for x

4x = 90

Divide both sides by 4

\frac{4x}{4} = \frac{90}{4}

x = 22.5

The measure of the complementary angles are:

x = 22.5°

3x = 3(22.5) = 67.5°

6 0
3 years ago
Please help. I will give brainliest.
jolli1 [7]
The value calculated by adding all the values of in a data set and dividing the sum by the number of values → Mean

The middle value when all the values are in order from least to greatest → Median

The value that appears most often in a data set → Mode

Hope this helped :)
8 0
4 years ago
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