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1 year ago

1.

Mathematics

2 answers:

oksian1 [2.3K]1 year ago

6 0

Answer:

Answer is 2

${ \rm{4x + 2 > 10}} \\ \\ { \rm{4x < 8}} \\ \\ { \rm{x < 2}}$

kogti [31]1 year ago

6 0

The answer is 2 I know this because i know this

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PLEASE HELP ME asap Compare the two ratios by entering >, < , or = in the box.

Leto [7]

1/8 = 0.125
3/20 = 0.150

Therefore 1/8 < 3/20

7 0

3 years ago

Find the exterior angle of a regular decagon

mamaluj [8]

Answer:

Exterior Angle = 36 degrees

Step-by-step explanation:

Each interior angle of a regular decagon measures 144 degrees.

=> We'll subtract 144 from 180 to get the measure of the exterior angle.

=> Exterior Angle = 180-144

=> Exterior Angle = 36 degrees

6 0

3 years ago

Andreas patio is composed of a rectangle and a semi circle as shown in the figure below which is the best estimate of the area o

Vladimir79 [104]

Answer:

38.13m²

Step-by-step explanation:

We find the area of ;

Rectangule and semicircle

Area of rectangle :

Length * width

Length = 8m ; width = 3m

Area = 8 * 3 = 24m²

Area of semicircle = 1/2 πr²

Radius, r = 3m

A = 1/2 * 3.14 * 3²

A = 1/2 * 3.14 * 9

A = 14.13 m²

Area of patio :

(24 + 14.13)m²

= 38.13m²

8 0

2 years ago

A gas is said to be compressed adiabatically if there is no gain or loss of heat. When such a gas is diatomic (has two atoms per

Tems11 [23]

Answer:

The pressure is changing at $\frac{dP}{dt}=3.68$

Step-by-step explanation:

Suppose we have two quantities, which are connected to each other and both changing with time. A related rate problem is a problem in which we know the rate of change of one of the quantities and want to find the rate of change of the other quantity.

We know that the volume is decreasing at the rate of $\frac{dV}{dt}=-4 \:{\frac{cm^3}{min}}$ and we want to find at what rate is the pressure changing.

The equation that model this situation is

$PV^{1.4}=k$

Differentiate both sides with respect to time t.

$\frac{d}{dt}(PV^{1.4})= \frac{d}{dt}k\\$

The Product rule tells us how to differentiate expressions that are the product of two other, more basic, expressions:

$\frac{d}{{dx}}\left( {f\left( x \right)g\left( x \right)} \right) = f\left( x \right)\frac{d}{{dx}}g\left( x \right) + \frac{d}{{dx}}f\left( x \right)g\left( x \right)$

Apply this rule to our expression we get

$V^{1.4}\cdot \frac{dP}{dt}+1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}=0$

Solve for $\frac{dP}{dt}$

$V^{1.4}\cdot \frac{dP}{dt}=-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}\\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}}{V^{1.4}} \\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}$

when P = 23 kg/cm2, V = 35 cm3, and $\frac{dV}{dt}=-4 \:{\frac{cm^3}{min}}$ this becomes

$\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}\\\\\frac{dP}{dt}=\frac{-1.4\cdot 23 \cdot -4}{35}}\\\\\frac{dP}{dt}=3.68$

The pressure is changing at $\frac{dP}{dt}=3.68$ .

7 0

3 years ago

A cubical block of metal weighs 6 pounds. How much will another cube of the same metal weigh if its sides are twice as long?

ser-zykov [4K]

I believe it would be 12, I believe this because its states that it is TWICE as long therefore is made from the same metal so 6x2=12

8 0

2 years ago