B. Yes, (1,4) is a solution
Answer:
We have to prove
sin(α+β)-sin(α-β)=2 cos α sin β
We will take the left hand side to prove it equal to right hand side
So,
=sin(α+β)-sin(α-β) Eqn 1
We will use the following identities:
sin(α+β)=sin α cos β+cos α sin β
and
sin(α-β)=sin α cos β-cos α sin β
Putting the identities in eqn 1
=sin(α+β)-sin(α-β)
=[ sin α cos β+cos α sin β ]-[sin α cos β-cos α sin β ]
=sin α cos β+cos α sin β- sinα cos β+cos α sin β
sinα cosβ will be cancelled.
=cos α sin β+ cos α sin β
=2 cos α sin β
Hence,
sin(α+β)-sin(α-β)=2 cos α sin β
Answer:14-1/3 if that makes sense to you
Step-by-step explanation:
Green Line:
This is a horizontal line at x = 0, so it would be:
x ? 0
Since the shaded area is going to the left of 0 (this means x is negative):
x ≤ 0
Blue Line:
The shaded area is below the line, so:
y ≤ mx + b
When x = 0, y is -5.
y ≤ mx - 5
From each point, you go up 3 units, and to the right 4 units, so the slope is 
.
Combination event: 2 or more simple events/actions
The correct answer is D) because there are 2 actions in one description.
