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kaheart [24]
3 years ago
9

Angle P and angle Q are supplementary. If angle P = 2x and angle Q = x-3, find X

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
8 0
2x+x-3=180
3x-3=180
3x=183
x=61
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85×250=_______ + 387= _______
Neko [114]

Answer:

21,637

Step-by-step explanation:

You can just use a caculator- Or simple multiplication by putting it on top of eachother.

You can do this many ways,just multiply with pen and paper,put 250 on top,and 85 on bottom which is 21,250,the add from there!

Hope I helped!!

7 0
2 years ago
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Tony makes a 5% commission on all his sales If his commission check is for $152.00 then what were Tony’s sales
shepuryov [24]

Answer:

i think its 7.60 but idk for sure

3 0
3 years ago
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Find the exact solutions and simplify as much as possible: 3x^2+1=6x
svetoff [14.1K]

Answer:

\frac{3+ \sqrt{6} }{3} and \frac{3- \sqrt{6} }{3}

Step-by-step explanation:

This is a quadratic equation, so we start by rearranging its terms so we can apply the quadratic formula:

ax^2+bx+c=0 has two possible solutions given by:

x=\frac{-b+/- \sqrt{b^2-4ac} }{2a}

So we rearrange the terms in the given quadratic equation bringing all terms to the left hhand side of the equal sign:

3x^2+1=6x\\3x^2-6x+1=0

The solutions will then be:

x=\frac{6+/- \sqrt{36-4(3)(1)} }{2(3)}=\frac{6+/- \sqrt{36-12} }{6}=\frac{6+/- \sqrt{24} }{6}=\frac{6+/- \sqrt{4*6} }{6}=\frac{6+/- 2\sqrt{6} }{6}=\frac{3+/- \sqrt{6} }{3}

Therefore the two possible answer are: \frac{3+ \sqrt{6} }{3} and \frac{3- \sqrt{6} }{3}

5 0
3 years ago
Find the area of a triangle with base of 10 ​inches and a height of 5 inches
Nataliya [291]

Answer:

C . 25 square inches

Explanation:

7 0
2 years ago
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A greeting card has a perimeter of 80 cm and an area of 384 square cm what are the dimensions for the greeting card
Ulleksa [173]

Step-by-step explanation:

it is a rectangle (usually).

so,

2×length + 2×width = 80

therefore, length + width = 40

length×width = 384

length = 384/width

384/width + width = 40

384 + width² = 40×width

width² - 40×width + 384 = 0

the general solution for such a square equation is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

x = width

a = 1

b = -40

c = 384

width = (40 ± sqrt((-40)² - 4×1×384))/(2×1) =

= (40 ± sqrt(1600 - 1536))/2 =

= (40 ± sqrt(64))/2 = (40 ± 8)/2 =

= 20 ± 4

width1 = 20 + 4 = 24 cm

length1 = 40 - 24 = 16 cm

width2 = 20 - 4 = 16 cm

length2 = 40 - 16 = 24 cm

so, both solutions are the same.

the greeting card is 24×16 cm. or 16×24, depending on how you are holding it.

3 0
2 years ago
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