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Vera_Pavlovna [14]
3 years ago
9

What is the diameter of a circle with a 4.2 cm radius

Mathematics
1 answer:
4vir4ik [10]3 years ago
3 0

Answer:

8.4cm

Step-by-step explanation:

In a circle, d = 2r, so d = 2 * 4.2cm = 8.4cm

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16 rounded to the nearest number is 20 im not sure if i helped you though
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Which one is it A. B. C. or D.
nadya68 [22]
7x + 2y = 2
2x - y = 10

2y = - 7x + 2
- y = - 2x + 10

2y = -7x + 2
y = 2x - 10

y=\frac{-7x+2}{2}
y= 2x - 10

y = -3.5x + 1
y =  2x - 10

Now, let's find "x" first by doing a substituion !

2x - 10 = - 3.5x + 1
y = 2x - 10

2x + 3.5x = 1 + 10
y = 2x - 10

5.5x = 11
y= 2x - 10

x =  \frac{11}{5.5}=2
y= 2*2 - 10 = 4 - 10 = -6

In short, the answer would be : y = -6 (Option B).

Hope this helps !

Photon



8 0
3 years ago
What is the value of x in the equation 3x -
shusha [124]
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2 years ago
Solve using the quadratic formula: 2n^2= 6n - 2
bekas [8.4K]

Answer:

n_1=(3 + 1\sqrt{5} )/2\\\\n_2=(3 - 1\sqrt{5} )/2

Step-by-step explanation:

2n^2= 6n - 2\\\\2n^2-6n+2=0\\\\a=2\\\\b=-6\\\\c=2

n=(-b \pm \sqrt{b^2-4ac} )/2a\\\\n=(-(-6) \pm \sqrt{(-6)^2-4(2)(2)} )/2(2)\\\\n=(6 \pm \sqrt{36-16} )/4\\\\n=(6 \pm \sqrt{20} )/4\\\\n=(6 \pm 2\sqrt{5} )/4\\\\n=(3 \pm 1\sqrt{5} )/2\\\\n_1=(3 + 1\sqrt{5} )/2\\\\n_2=(3 - 1\sqrt{5} )/2

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2 years ago
Please solve!!!! I have been trying to figure out for the past 20 years of my life>
Kobotan [32]

Answer:

ergerge

Step-by-step explanation:

5 0
2 years ago
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