1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
LenaWriter [7]
3 years ago
6

At sea level, earths atmosphere exerts a pressure of 1 atmosphere. Atmospheric pressure P (in atmospheres) decreases with altitu

de and can be modeled by P = (0.99987)a where a is the altitude (in meters) identify the initial amount, decay factor, and decay rate
Mathematics
2 answers:
PtichkaEL [24]3 years ago
5 0

Answer:

Initial Amount=1

Decay Factor=0.99987

Decay Rate=0.013%

Step-by-step explanation:

If P = 0.99987ᵃ

I. Initial amount

The initial amount is when a=0

P = 0.99987⁰ = 1

The Pressure at Sea Level=1

II. Decay factor

This is like the decay constant. From the model, P = 0.99987ᵃ, the decay constant/factor is 0.99987.

III. Decay Rate = 1-0.99987 = 0.00013

Expressed in Percentage = 0.013%

irakobra [83]3 years ago
5 0

Answer:

The answers to the question are as follows

Initial a amount = 1

Decay Factor =0.99987

Decay rate = 1-0.99987 = 0.00013

Step-by-step explanation:

We have the formula for exponential decay given by

y = a(1-b)^t

In the above we have  (1+b)  = Decay factor

a = Initial amount

b =  rate of decay

t = time

Comparing y = a(1-b)^t , with the function in the question, we have

a(1-b)^t≡ 0.99987^a

Therefore, a ≡ 1,

1 + b ≡ 0.99987 and

x ≡ a

Therefore we have

Initial amount = 1

Decay/growth factor = 0.99987

But rate of decay = b = 1-(1-b) =b

Therefore Rate of Decay = 1 - 0.99987

You might be interested in
Gcf of 63 and 27 i will give toy 12pts
NeTakaya
GCF is 3×3 so it is 9
4 0
3 years ago
What is the length of leg sof the triangle below?<br> 90°
miskamm [114]
Not sure I’m sorry, have you tried google
5 0
3 years ago
Having serious block because of the units The density of mercury is 13.6 g/cm3. What approximate mass of mercury is required to
mart [117]
I would approach the problem like this:

1 oz bottle.............................30cm^3
33 oz bottle.............................xcm^3

in a 33 oz bottle will be x=33*30=990cm^3
density=mm/v
13.6g/cm^3= m/ 990cm^3
m= 13.6 * 990=13464 g
or 13.464 kg in a 33 oz bottle
3 0
3 years ago
Circumference of the circle
Alja [10]

Answer:

37 5/7

Step-by-step explanation:

use formular it will be 2pie -22/7 ×radius

since we have been given only radius it will be

2×22/7×6=37 5/7

8 0
2 years ago
Read 2 more answers
Please help...............
Korvikt [17]

Answer:

-|b| < b

Step-by-step explanation:

-b where?

5 0
3 years ago
Other questions:
  • 2x – 4y = 14<br> x = 2y – 2<br><br> What is the solution to the system?
    13·1 answer
  • hi:) my teacher taught another method but she said we’ll only be learning it next year. I didn’t understand it , anyone able to
    11·1 answer
  • How would you write the following expression as a single term? 3[2 ln(x-1) - lnx] + ln (x+1)
    8·1 answer
  • the morgan famili and the alexander family each ised their sprinkles last summer. the water output was 20. l per hour. The water
    13·1 answer
  • Use the quadratic equation x^2+3x+5=0 to answer the questions. A: What is the discriminant of the quadratic equation? B: Based o
    8·2 answers
  • What is the y and x intercepts .
    11·1 answer
  • I don’t get it I need help solving this math problem I
    8·1 answer
  • onah’s sister is 10 years old. Jonah is 8 years younger than twice his sister’s age. Write an expression for Jonah’s age.
    6·2 answers
  • 10 + 6x + 2x - 7 = 35<br> Help me pls and ty
    8·2 answers
  • Elaine is making a flower garden with rows of flowerS The garden is 20 yards long. She wants a total of 7 rows of flowers that a
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!