Question

The net of an isosceles triangular prism is shown. What is the surface area, in square units, of the triangular prism?

Answer 1

I believe the answer is 88units^2

Answer 2

Answer:  First option is correct.

Step-by-step explanation:

Since we have given that

Dimensions of lower most rectangle is 4 meters long and 5 meters wide.

So, Area of 2 lower and upper rectangle is

$2\times Length\times breadth\\\\=2\times 4\times 5\\\\=40\ sq.\ units$

Dimensions of middle rectangle is 6 units and 4 meters long.

Area of middle rectangle is given by

$Length\times breadth\\\\=4\times 6\\\\=24\ sq.\ units$

Dimensions of triangle are as follows:

Height = 4 units and base = 6 units.

So, Area of 2 triangles would be

$2\times \dfrac{1}{2}\times 6\times 4\\\\=24\ sq.\ units$

So, Total surface area of the triangular prism is given by

40+24+24

=40+48

=84 sq. units

Hence, First option is correct.