The net of an isosceles triangular prism is shown. What is the surface area, in square units, of the triangular prism?
2 answers:
Answer: First option is correct.
Step-by-step explanation:
Since we have given that
Dimensions of lower most rectangle is 4 meters long and 5 meters wide.
So, Area of 2 lower and upper rectangle is
Dimensions of middle rectangle is 6 units and 4 meters long.
Area of middle rectangle is given by
Dimensions of triangle are as follows:
Height = 4 units and base = 6 units.
So, Area of 2 triangles would be
So, Total surface area of the triangular prism is given by
40+24+24
=40+48
=84 sq. units
Hence, First option is correct.
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Option B:
Law of cosine, two sides and the included angle are known.
Solution:
Let us first know the law of cosines and law of sines.
Law of cosine:
If we know the sides a, b and the included angle θ, then we can find the third side c. This is known as the law of cosine.
Law of sine:
The sides of a triangle are to one another in the same ratio as the sines of their opposite angles.
Given ∠P and the sides r, q are known.
<u>To find the value of p:</u>
Option A: Law of cosines, all sides are known.
It is false by the above definition of law of cosine.
Option B: Law of cosine, two sides and the included angle are known.
It is true by the above definition of law of cosine.
Option C: Law of sines, all sides are known.
It is false, because one angle is given in question.
Option D: Law of sines, two angles and the included side are known.
It is false, because two angles are not given.
Option B is the correct answer.
Hence the answer is "Law of cosine, two sides and the included angle are known".