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Nina [5.8K]
3 years ago
12

What is the equation of the line that is parallel to the line y =-1\3

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
5 0

Hello!

If a you want to find an equation of the line that is parallel to the given line, we must know that if two lines are parallel, then their slope will <em>always</em> have to be equal.

This means that the new equation must have a slope of -1/3.

Also, you would need to substitute the given point (6, 8) into the equation with the slope: -1/3 as well. Following these steps allows you to find the equation of line.

y = -1/3x + b (6, 5)

5 = -1/3(6) + b

5 = -2 + b (add 2 to both sides)

7 = b

Therefore, the equation of the line is y = -1/3x + 7.

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8/7=x/5 what is the value of x round to the nearest tenth
faust18 [17]

Answer:

<h2>x = 5.7</h2>

Step-by-step explanation:

\frac{8}{7}  =  \frac{x}{5}

To find x first cross multiply

We have

7x = 8 × 5

7x = 40

Divide both sides by 7

That's

\frac{7x}{7}  =  \frac{40}{7}

x =  \frac{40}{7}

x = 5.7142

We have the final answer as

<h3>x = 5.7 to the nearest tenth</h3>

Hope this helps you

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3 years ago
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2 years ago
2 4/5 - 1 3/10 + 6 7/15
Tomtit [17]

Answer:7.967

Step-by-step explanation:

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3 years ago
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A survey asked people to name their favorite season. The results of the survey showed that 34% said spring and 15% said fall. Wh
max2010maxim [7]

Answer:

D. 29% and 22%

Step-by-step explanation:

The known percentages are 34% and 15%. Add these two together to get 49%. All four choices should add up to 100%. So subtract to find what remains:

100% - 49%

= 51%

We don't actually have enough information to determine the percents for summer and winter. BUT the only answer that adds up to 51% is answer D. 29% and 22%.

8 0
2 years ago
-2.7f + 0.3f - 16 - 4=
suter [353]

Answer:

-2.4f or -8 1/3

Step-by-step explanation:

I am not sure what should be at the end of the equal sign but if it is to simplify it would be -2.4f-20

If you want to solve then you get -2.4f=20 so f=-20/2.4 which equal to -8 1/3

3 0
2 years ago
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