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3 years ago

What is the equation of the line that is parallel to the line y =-1\3

Mathematics

1 answer:

PilotLPTM [1.2K]3 years ago

5 0

Hello!

If a you want to find an equation of the line that is parallel to the given line, we must know that if two lines are parallel, then their slope will always have to be equal.

This means that the new equation must have a slope of -1/3.

Also, you would need to substitute the given point (6, 8) into the equation with the slope: -1/3 as well. Following these steps allows you to find the equation of line.

y = -1/3x + b (6, 5)

5 = -1/3(6) + b

5 = -2 + b (add 2 to both sides)

7 = b

Therefore, the equation of the line is y = -1/3x + 7.

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The mean length of 5 childrens' index finger is 5.6cm.

Brilliant_brown [7]

The mean length (rounded to 2 DP) of these 8 people's index finger is 5.83

<h3>What is the mean length (rounded to 2 DP) of these 8 people's index finger?</h3>

The given parameters are:

Children

Mean = 5.6 cm

Frequency = 5

Adult

Mean = 6.2 cm

Frequency = 3

The mean length of these 8 people's index finger is calculated as:

$\bar x = \frac{\sum fx}{\sum f}$

So, we have

Mean = (5.6 * 5 + 6.2 * 3)/(5 + 3)

Evaluate

Mean = 5.83

Hence, the mean length (rounded to 2 DP) of these 8 people's index finger is 5.83

Read more about mean at

brainly.com/question/20118982

#SPJ1

7 0

1 year ago

Find the equation of the line passing through the points (7, 16) and (2, −4). Then state the slope and coordinates of the x- and

Elanso [62]

Answer:

Equation point-slope model is: y-16 = 4 (x-7)

Slope =4

x-intercept=(7,2)

y-intercept=(16,-4)

Step-by-step explanation:

6 0

3 years ago

Write the ratio 7/8 in two different forms

Rainbow [258]

You can write it
7 to 8
7:8

5 0

3 years ago

the distance from jeffreys bay knysna is 198km .A driver is 11:at knysna. calculate the drivrs average speed

zavuch27 [327]

Answer:

18km/[unit of time]

Step-by-step explanation:

v (speed) = d/t

v = 198/11

v = 18

8 0

2 years ago

Find x Thanks for the help in advance!

Marina86 [1]

I'm not sure if this is the easiest way of doing this, but it surely work.

Let the base of the triangle be AB, and let CH be the height. Just for reference, we have

$AH=2,\quad HB=6,\quad AC=x$

Moreover, let CH=y and BC=z

Now, AHC, CHB and ABC are all right triangles. If we write the pythagorean theorem for each of them, we have the following system

$\begin{cases}4+y^2=x^2\\36+y^2=z^2\\x^2+z^2=64\end{cases}$

If we solve the first two equations for y squared, we have

$y^2=x^2-4\\y^2=z^2-36$

And we can deduce

$z^2 = x^2+32$

So that the third equation becomes

$x^2+x^2+32=64 \iff 2x^2 = 32 \iff x^2=16 \iff x=4$

(we can't accept the negative root because negative lengths make no sense)

7 0

3 years ago