What is the degree of the polynomial function shown in the graph?

Mathematics

2 answers:

Ivahew [28]3 years ago

4 0

The correct answer is

dusya [7]3 years ago

3 0

The answer to your Q is 4

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Answer:

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4 years ago

Find the axis of the graph of the function..f(x) = 4x2 + 8x + 7

SpyIntel [72]

F ( x ) = 4 x² + 8 x + 7
a = 4, b = 8
The axis formula is:
x = - b / 2 a
x = - 8 / (2*4) = - 8 / 8 = -1
Answer:
The axis of the graph of the function is x = - 1.

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3 years ago

What are the possible values of x in 8x2 + 4x = -1?

Westkost [7]

Answer:

The possible values of x are:

x= $\frac{-1+\sqrt{3}}{4} \,\,or\,\, x= 0.18$

and

x= $\frac{-1-\sqrt{3}}{4} \,\, or \,\, x= -0.68$

Step-by-step explanation:

$8x^2+4x+1=0$

Using Quadratic formula to solve this equation:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\a = 8 \,\, b = 4\,\, c = -1\\Putting \,\, values \,\, in \,\, the\,\, equation\\x= \frac{-4\pm\sqrt{(4)^2-4(8)(-1)}}{2(8)}\\x= \frac{-4\pm\sqrt{16+32}}{16}\\x= \frac{-4\pm\sqrt{48}}{16}\\x= \frac{-4+ \sqrt{48}}{16} \,\, and \,\, x= \frac{-4- \sqrt{48}}{16}\\x= \frac{-1+ \sqrt{3}}{4} \,\, and \,\, x= \frac{-1- \sqrt{3}}{4}$